Determine the growth factor corresponding to 1% increase

Mathematics

2 answers:

bezimeni [28]4 years ago

4 0

Not sure but I would say 0.1 again I am not sure that that is what is asking for

Juliette [100K]4 years ago

3 0

For an increase of percentage, it is a growth factor.

For a decrease of percentage, it is a decay factor.

The growth factor is = (1+r)

The decay factor is= (1-r)

As it is increase of 1%, it is a growth factor.

Here the rate of increase is 1% = 1/100 = 0.01

Hence the growth factor is 1 + 0.01 = 1.01

The growth factor corresponding to 1% increase is 1.01.

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Write the standard equation for the hyperbola with the following conditions: vertices: (-2, -3) and (6, -3) foci: (-4, -3) and (

STALIN [3.7K]

Hello,

Vertices are on a line parallele at ox (y=-3)

The hyperbola is horizontal.

Equation is (x-h)²/a²- (y-k)²/b²=1

Center =middle of the vertices=((-2+6)/2,-3)=(2,-3)
(h+a,k) = (6,-3)
(h-a,k)=(-2,-3)
==>k=-3 and 2h=4 ==>h=2
==>a=6-h=6-2=4 (semi-transverse axis)

Foci: (h+c,k) ,(h-c,k)
h=2 ==>c=8-2=6

c²=a²+b²==>b²=36-4²=20

Equation is:
$\boxed{ \dfrac{(x-2)^2}{16} - \dfrac{(y+3)^2}{20} =1}

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