5z>15-----subtract 2 on both sides
z>3----divide by 5
therefore, z must equal -10, or -4
The common factor in both terms is 10<span />
1) The x-axis represents the energy (
), in joules. The y-axis represents the amplitude (
), in milimeters.
2) The curve depicts an <em>monotonous decrecent</em> rate of change.
3) The amplitude is directly proportional to the root square of the energy.
<h3>How to analyze a graph relationship between two variables</h3>
In this question we have a relationship between two variables, in which we must apply principles of <em>functional</em> analysis to respond three questions presented in the statement.
Now we proceed to answer the three questions below:
- <em>What is on the x-axis? The y-axis?</em> R/ The x-axis represents the energy (
), in joules. The y-axis represents the amplitude (
), in milimeters. - <em>How would you describe the rate of change of the line?</em> R/ The curve depicts an <em>monotonous decrecent</em> rate of change, that is, the slope converges to zero when the energy tends to infinite.
- <em>What does this tell you about the relationship between amplitude and energy?</em> R/ The curve show a strong similarity with a function of the form
. Hence, the amplitude is directly proportional to the root square of the energy.
To learn more on functions, we kindly invite to check this verified question: brainly.com/question/12431044
Answer:
(a) 169.1 m
Step-by-step explanation:
The diagram shows you the distance (x) will be shorter than 170 m, but almost that length. The only reasonable answer choice is ...
169.1 m
__
The relevant trig relation is ...
Cos = Adjacent/Hypotenuse
The leg of the right triangle adjacent to the marked angle is x, and the hypotenuse is 170 m. Putting these values into the equation, you have ...
cos(6°) = x/(170 m)
x = (170 m)cos(6°) ≈ (170 m)(0.994522) ≈ 169.069 m
The horizontal distance covered is about 169.1 meters.
_____
<em>Additional comment</em>
Expressed as a percentage, the slope of this hill is tan(6°) ≈ 10.5%. It would be considered to be a pretty steep hill for driving.