SA=2hpir+2pir^2=2pir(h+r)
V=hpir^2
SA=339
r=6
339=2pir(h+r)
339=2pi3(h+3)
339=6pi(h+3)
divide both sides by 6pi
56.5/pi=h+3
minus 3 both sides
(56.5/pi)-3=h
(56.5-3pi)/pi=h
v=hpir^2
v=((56.5-3pi)/pi)(pi)(6)^2
v=(56.5-3pi)(36)
v=2034-108pi
use pi=3.141592
v=1694.7079934123023302460345146058
round
1695 cubic cm
First, solve for the radius of the sphere using the volume and the equation,
V = 4πr³ / 3
Substituting for the known values,
3000π m³ = 4πr³/3
The value of r from the equation is approximately 13.10 meters. The equation for the surface area is,
SA = 4πr²
Substituting the value of radius,
SA = 4π(13.10 m)² = 2157.74 m²
Therefore, the surface area is approximately 2157.74 m².
as you increase an object's size, you are increasing its volume by the increase cubed, volume is a 3D quantity, and its surface are by the increase squared surface area is a 2D quantity.
Answer:
step-by-step-explaination:
y=2.2