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3 years ago

What is .7899 rounded 4 decimal places

1 answer:

3 0

.7899 rounded is .79. But in you want to convert/round it all the way it’s 1. But .79 makes more sense. Or .8. Which ever one works!!

Hope this helped. :)

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IrinaK [193]

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Question 1: photographs

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3 years ago

Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the

KiRa [710]

Answer:

395, 17.212

(360.576,429.424)

Step-by-step explanation:

Given that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p.

Here $n=1580and p =1/4 =0.25\\q = 0.75\\np = 395 and\\nq = 1185$

Since np and nq are greater than 5 by rule of thumb we can approximate binomial to normal.

Mean = np = 395

Variance = npq = $395*0.75=296.25$

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Thus X no of successes is N(395, 17.212)

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3 years ago

Which is an equivalent form of the first equation that when added to second equation eliminates the x terms? 4/5 x-3/5y=18

Fittoniya [83]

Answer:

$-8x + 6y = -180$

Step-by-step explanation:

Given

$\frac{4}{5} x-\frac{3}{5}y=18$

$8x + 12y = 11$

Required

Equivalent form of the first equation that eliminates x when added to the second

To do this, we simply make the coefficients of x to be opposite in both equations.

In the second equation, the coefficient of x is 8.

So, we need to make the coefficient of x -8, in the first equation.

$\frac{4}{5} x-\frac{3}{5}y=18$

Multiply by -10

$-10 * [\frac{4}{5} x-\frac{3}{5}y=18]$

$\frac{-40}{5} x+\frac{30}{5}y=-180$

$-8x + 6y = -180$

<em>When this is added to the first equation, the x terms becomes eliminated</em>

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3 years ago

Jermaine has a collection of 36 baseball cards. He gives 2/3 of his collection to his brother. How many baseball cards does he g

zepelin [54]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Misty wishes to obtain 85 ounces of a 40% acid solution by combining a 72% acid solution with a 25% acid solution. How much of e

Y_Kistochka [10]

13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed

<u>Step-by-step explanation:</u>

Total mass of acid required= 85 ounces

Let the mass of 72% acid be 'a'

Let the mass of 25% acid be 'b'

a + b = 85

b = 85-a

85(40/100) = a(72/100) + b(25/100)

85(2/5) = a(72/100) +(85- a) (25/100)

34 = (72a/100) + (2125/100) - (25a/100)

34 - (2125/100) = (72a + 25a) /100

(3400-2125)/100 = 97a /100

97a = 1275

a = 13.15 ounces

b = 85 - 13.14

b = 71.85 ounces

13.15 ounces of 72% acid and 71.85 ounces of 25% acid are needed

4 0

3 years ago