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3 years ago

The campers in cabin a walked 1/4 of the way to otter ridge which is 13 miles. How do i figure out how many miles they walked?

2 answers:

6 0

You can model the situation by 13/x=1/4, where x is the distance to otter ridge. you then cross multiply, getting you to x=52

Tema [17]3 years ago

4 0

$Multiply\ fraction\ times \ all\ distance\\\\ \frac{1}{4}*13miles=\frac{13}{4}miles=3\frac{1}{4}miles\\\\
They\ walked\ 3\frac{1}{4}miles.$

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A rectangular carpet measures 12m by 5m. Part of the carpet is covered by a square rug of length 2m. What fraction of the carpet

guajiro [1.7K]

Answer:

¹/15

Step-by-step explanation:

Area of the rug = s²

Where s = 2 m

Area of the rug = 2² = 4 m²

Area of the rectangular carpet = length × width

Where,

Length = 12 m

Width = 5 m

Area = 12 × 5 = 60 m²

Fraction of the carpet covered by the rug = area of the rug ÷ area of the carpet = 4/60 = ¹/15

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3 years ago

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Stels [109]

Answer:

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2 years ago

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Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

30 Points!!!!

irina1246 [14]

Answer:

The answer is four months

Step-by-step explanation:

You have a starting cost of $50 with a $20 fee every month

You have a starting cost of $30 with a $25 fee every month

Start: $50 ($20 per month)

M1 = $70, M2 = $90, M3 = $110, M4 = $130

Start: $30 ($25 per month)

M1 = $55, M2 = $80, M3 = $105, M4 = $130

In conclusion, the prices of the two will match at Month 4

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3 years ago

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Setler79 [48]

1300%

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3 years ago