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3 years ago

10

heeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

eeeeeeeeeelp

1 answer:

yaroslaw [1]3 years ago

7 0

Answer:

D

Step-by-step explanation:

sorry can't explain

but it helps you

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&= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12} S = square numbers E = even numbers Complete the Venn diagram. E, S 4 2,6 8, 10,

Umnica [9.8K]

The remaining elements if Venn diagram is S= { 4, 9}

<h3>What is Venn diagram?</h3>

A Venn diagram uses overlapping circles or other shapes to illustrate the logical relationships between two or more sets of items.

Given:

E = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 }

S = square numbers

E = even numbers

Element in set S= { 4, 9}

Learn more about Venn diagram here:

brainly.com/question/1605100

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2 years ago

Find the slope of the line through (2, -3) and (-4, 3).

Mars2501 [29]

Answer:

Slope= -1x OR -x

Step-by-step explanation:

rise over run: y2 - y1 / x2 - x1

= 3 - (-3) / -4 - 2

= 6 / -6

= -1

3 0

4 years ago

Read 2 more answers

Jeff spent $7.50 at the store. He bought a notebook for $4.00. He also bought 10 pencils. How much did each cost?

DedPeter [7]

Subtract 7.50 - 4.00 and dived that answer by 10

7 0

4 years ago

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Hawick is 1515 miles south of Abbotsford, and Kelso is 1717 miles east of Abbotsford. What is the distance from Hawick to Kelso?

Mashcka [7]

Answer:

As per the statement:

Hawick is 15 miles south of Abbotsford, and Kelso is 17 miles east of Abbotsford.

Let H represents Hawick , A represents Abbotsford and K represents Kelso

See the diagram as shown below:

Distance of AH = 15 miles

Distance of AK = 17 miles.

We have to find the distance HK:

Using Pythagoras theorem;

$\text{Hypotenuse side}^2 = \text{Adjacent side}^2 + \text{opposite side}^2$

then;

$\text{HK}^2 = 15^2+17^2 = 225 + 289 = 514$

or

$HK = \sqrt{514} =22.671581$ miles.

Therefore, the distance from Hawick to Kelso( to the nearest tenth place) is 22.6 miles

5 0

3 years ago

Read 2 more answers

a rectangle has a diagonal 20 inches long that forms angles of 60 and 30 with the sides. find the perimeter of the rectangle.

kakasveta [241]

Answer:

P = 47.32

Step-by-step explanation:

This triangle is a special triangle. Because it is 30-60-90 it will have measurements similar to $1 - \sqrt{3} - 2$ . If the longest side is 20 then it corresponds to 2. This means the shortest side of 1 corresponds to half this or 10.

So the triangle will have sides $10 - 10\sqrt{3} - 20$ .

To find the perimeter add all these lengths.

$P = 10 + 10\sqrt{3} +20\\P = 30+10\sqrt{3} \\ P = 47.32$

8 0

4 years ago