Please help with any you can
1 answer:
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Step-by-step explanation:
You said the other one would be the last haha just kidding I'm glad to help.
16.
First, get rid of that parenthesis.
Now multiply both sides by 2 so that you can isolate k
19.
This is a pretty easy one. If you didn't know, 121/11 is actually 11 :)
Simply multiply by 3 to isolate r :)
Check the picture below.
so notice, the sides AB and AC you can pretty much count them off the grid.
now, to get the CB side.
![\bf \textit{distance between 2 points}\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) C&({{ -5}}\quad ,&{{ 1}})\quad % (c,d) B&({{ 3}}\quad ,&{{ -5}}) \end{array}\qquad % distance value d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2} \\\\\\ CB=\sqrt{[3-(-5)]^2+[-5-1]^2}\implies CB=\sqrt{(3+5)^2+(-5-1)^2} \\\\\\ CB=\sqrt{8^2+(-6)^2}\implies CB=\sqrt{100}\implies CB=10](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bdistance%20between%202%20points%7D%5C%5C%20%5Cquad%20%5C%5C%0A%5Cbegin%7Barray%7D%7Blllll%7D%0A%26x_1%26y_1%26x_2%26y_2%5C%5C%0A%25%20%20%28a%2Cb%29%0AC%26%28%7B%7B%20-5%7D%7D%5Cquad%20%2C%26%7B%7B%201%7D%7D%29%5Cquad%20%0A%25%20%20%28c%2Cd%29%0AB%26%28%7B%7B%203%7D%7D%5Cquad%20%2C%26%7B%7B%20-5%7D%7D%29%0A%5Cend%7Barray%7D%5Cqquad%20%0A%25%20%20distance%20value%0Ad%20%3D%20%5Csqrt%7B%28%7B%7B%20x_2%7D%7D-%7B%7B%20x_1%7D%7D%29%5E2%20%2B%20%28%7B%7B%20y_2%7D%7D-%7B%7B%20y_1%7D%7D%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0ACB%3D%5Csqrt%7B%5B3-%28-5%29%5D%5E2%2B%5B-5-1%5D%5E2%7D%5Cimplies%20CB%3D%5Csqrt%7B%283%2B5%29%5E2%2B%28-5-1%29%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0ACB%3D%5Csqrt%7B8%5E2%2B%28-6%29%5E2%7D%5Cimplies%20CB%3D%5Csqrt%7B100%7D%5Cimplies%20CB%3D10)
sum all three sides up, and that's the perimeter of the triangle.
so notice, the sides AB and AC you can pretty much count them off the grid.
now, to get the CB side.
sum all three sides up, and that's the perimeter of the triangle.
Answer:
using Pythagorean theorem