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2 years ago

What angle are these?

Mathematics

1 answer:

Grace [21]2 years ago

5 0

Answer:

Corresponding Angles and Alternate Exterior

Step-by-step explanation:

The angles are corresponding if same side in a parallel.

This is because as the lines are parallel to one another that means that the next following angle measure is the same in approach.

For the other problems if they are opposite sides from one another.

They are called alternate exteriors.

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Hey, I need some help. Please solve the problem and give some steps.

Tatiana [17]

8.4x10=84x 5.6=470.4

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3 years ago

What is the mean absolute deviation for 3 3 4 5 5 4

nikitadnepr [17]

Answer as a fraction = 2/3

Answer in decimal form = 0.667 (approximate)

=======================================================

Explanation:

The first thing we need is to find the mean. Add up the values to get 3+3+4+5+5+4 = 24. Then divide by n = 6 since there are 6 values.

24/n = 24/6 = 4

The mean is 4

Now subtract the mean from each value

3-4 = -1
3-4 = -1
4-4 = 0
5-4 = 1
5-4 = 1
4-4 = 0

Apply absolute value to each result so that the difference is not negative.

We get this new list: {1, 1, 0, 1, 1, 0}

Now compute the mean of that new list to get the final answer

1+1+0+1+1+0 = 4

4/n = 4/6 = 2/3 = 0.667 approximately

8 0

3 years ago

Read 2 more answers

If x – 9 is a factor of x2 – 5x – 36, what is the other factor?

Luba_88 [7]

Answer:

x + 4

Step-by-step explanation:

(x - 9)(x + 4)

FOIL

x^2 + 4x - 9x - 36 = x^2 - 5x - 36

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4 years ago

Read 2 more answers

IN A CLASS OF 100 57 STUDENTS RECEIVED A GRADE A WHAT FRACTION DID NOT RECEIVE AN A

AysviL [449]

57/100 of students did not recieve an A

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3 years ago

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The spread of a virus is modeled by V (t) = −t 3 + t 2 + 12t,

VashaNatasha [74]

Functions can be used to model real life scenarios

The reasonable domain is $\mathbf{[0,\infty)}$ .
The average rate of change from t = 0 to 2 is 20 persons per week
The instantaneous rate of change is $\mathbf{V'(t) = -3t^2 + 2t + 12}$ .
The slope of the tangent line at point (2,V(20) is 10
The rate of infection at the maximum point is 8.79 people per week

The function is given as:

$\mathbf{V(t) = -t^3 + t^2 + 12t}$

(a) Sketch V(t)

See attachment for the graph of $\mathbf{V(t) = -t^3 + t^2 + 12t}$

(b) The reasonable domain

t represents the number of weeks.

This means that: t cannot be negative.

So, the reasonable domain is: $\mathbf{[0,\infty)}$

(c) Average rate of change from t = 0 to 2

This is calculated as:

$\mathbf{m = \frac{V(a) - V(b)}{a - b}}$

So, we have:

$\mathbf{m = \frac{V(2) - V(0)}{2 - 0}}$

$\mathbf{m = \frac{V(2) - V(0)}{2}}$

Calculate V(2) and V(0)

$\mathbf{V(2) = (-2)^3 + (2)^2 + 12 \times 2 = 20}$

$\mathbf{V(0) = (0)^3 + (0)^2 + 12 \times 0 = 0}$

So, we have:

$\mathbf{m = \frac{20 - 0}{2}}$

$\mathbf{m = \frac{20}{2}}$

$\mathbf{m = 10}$

Hence, the average rate of change from t = 0 to 2 is 20

(d) The instantaneous rate of change using limits

$\mathbf{V(t) = -t^3 + t^2 + 12t}$

The instantaneous rate of change is calculated as:

$\mathbf{V'(t) = \lim_{h \to \infty} \frac{V(t + h) - V(t)}{h}}$

So, we have:

$\mathbf{V(t + h) = (-(t + h))^3 + (t + h)^2 + 12(t + h)}$

$\mathbf{V(t + h) = (-t - h)^3 + (t + h)^2 + 12(t + h)}$

Expand

$\mathbf{V(t + h) = (-t)^3 +3(-t)^2(-h) +3(-t)(-h)^2 + (-h)^3 + t^2 + 2th+ h^2 + 12t + 12h}$ $\mathbf{V(t + h) = -t^3 -3t^2h -3th^2 - h^3 + t^2 + 2th+ h^2 + 12t + 12h}$