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GarryVolchara [31]
2 years ago
7

Find the equation of the line that is parallel to y=x-3 and contains the points (3,-2)

Mathematics
1 answer:
Degger [83]2 years ago
4 0
Answer:

y = [1]x + [-5 ]

Step-by-step explanation:

the equation is : y = ax+b

the slope is a : a =1 ( same slope parrallal to the line : y= x-3 )

the line that passes through (3, -2) : -2 = (3)+b
b = -5

the equation is : y = x-5
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7 0
3 years ago
Read 2 more answers
Please help me please I need help!!!!!!!!!!!!!!!!!!!hshdjdndndbdbnfjfkfkfkdkdkfkfjdjfiid
Serggg [28]

y = (x - 2)(x + 5)    First I would multiply (x - 2) and (x + 5) together

y = x² + 5x - 2x - 10

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Next I would plug in a number for x to find its y value. I will plug in 0

y = 0² + 3(0) - 10

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Your answer is Graph A because the y-intercept is (0,-10)

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