Find the equation of the line that is parallel to y=x-3 and contains the points (3,-2)

1 answer:

4 0

Answer:

y = [1]x + [-5 ]

Step-by-step explanation:

the equation is : y = ax+b

the slope is a : a =1 ( same slope parrallal to the line : y= x-3 )

the line that passes through (3, -2) : -2 = (3)+b
b = -5

the equation is : y = x-5

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