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1 year ago

Find the equation of the line that is parallel to y=x-3 and contains the points (3,-2)

1 answer:

4 0

Answer:

y = [1]x + [-5 ]

Step-by-step explanation:

the equation is : y = ax+b

the slope is a : a =1 ( same slope parrallal to the line : y= x-3 )

the line that passes through (3, -2) : -2 = (3)+b
b = -5

the equation is : y = x-5

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I need help finding the y-intercept of these, I am no good with slope and tables. ;-;

zubka84 [21]

Answer:

1. -4

2. 6

3. -6

(i hope this is right •_•)

Step-by-step explanation:

First table

When the x coordinate is 0, that point is your y intercept. For the first one, your y intercept is -4.

Second table

For the second one, we need to do a bit of counting. We can see the x coordinates go before and after zero, but the table does not show us 0. So, we're going to have to calculate the slope. Bear with me here, I'm a little tired and this might be rambling ;-;

So, the formula for calculating slope is $\frac{y_{2} -y_{1}}{x_{2}-x_{1}}$ . I'm going to use those first two points to get my slope. We're going to say the first point is point 1 and the second point is point 2 (genius, i know lol). So, let's substitute in the x and y values.

$\frac{9-12}{-3-(-6)}$

And simplify...

$\frac{-3}{3}$

So, your slope is -1. We can use that. We just have to count down.

If the x is -2, the y is 8. If the x is -1, the y is 7. And if the x is 0....(drumroll please) the y is 6! So, your y intercept is 6.

Third table

Now, this table isn't very nice either and doesn't have an x as 0 for us. Hmpf. But we can still do what we did above. I'll just skip the explanation and you can observe my steps.

$\frac{-3-(-5)}{9-3}$

$\frac{2}{6}$

$\frac{1}{3}$

Let's count down....

If x = 3, y = -5

If x = 2, y = -5 1/3

If x = 1, y = -5 2/3

If x = 0, y = -6

8 0

3 years ago

I figured out that it's A but i need to how many square yards is the combined area of the plot NO LINKS AND NO DOING IT JUST FOR

goblinko [34]

Answer:

I believe both are 80 or 40

Step-by-step explanation:

5 0

2 years ago

Please Help with angles!

777dan777 [17]

Step-by-step explanation:

003:

To solve this, we'll be using the Pythagorean theorem, $a^2+b^2=c^2$

$a^2+8^2=15^2\\a^2+64=225\\a^2=161\\a = \sqrt{161}$

004:

For the next couple questions we'll be using a fun rule called SOHCAHTOA, which stands for Sin (Opposite/Hypotenuse) Cos (Adjacent/Hypotenuse) Tan (Opposite/Adjacent). From this we can see that Tan θ is 8/ $\sqrt{161}$ .

005:

From this rule again, we can tell that sin Ф (Opposite/Hypotenuse) is going to be $\sqrt{161}$ /15.

Answer:

003: $\sqrt{161}$

004: 8/ $\sqrt{161}$

005: $\sqrt{161}$ /15

7 0

3 years ago

Help me out guys thanks

irga5000 [103]

Perpendicular bisector

4 0

2 years ago

Read 2 more answers

3 is what percent of 90?

Eddi Din [679]

Percentages
3% of 90 = 2.7 Dec 24 08:19 UTC (GMT)
1.3% of 50 = 0.65 Dec 24 08:19 UTC (GMT)
5% of 1,650 = 82.5 Dec 24 08:19 UTC (GMT)
61% of 1.618 = 0.98698 Dec 24 08:19 UTC (GMT)
76.56% of 309 = 236.5704

3 0

3 years ago

Read 2 more answers