Answer:
The y intercept should be 2 lower than the original equation
Step-by-step explanation:
Answer:
I think Quadrant 1. I;m not trying to just answer for the points
Step-by-step explanation:
Answer:
3 ÷ 0.25
Step-by-step explanation:
There are three squares, so 3.
Each square is divided into four squares,
One square out of four squares is,
1 / 4 = 0.25
Therefore,
3 ÷ 0.25
Answer:
See the attached figure which represents the problem.
As shown, AA₁ and BB₁ are the altitudes in acute △ABC.
△AA₁C is a right triangle at A₁
So, Cos x = adjacent/hypotenuse = A₁C/AC ⇒(1)
△BB₁C is a right triangle at B₁
So, Cos x = adjacent/hypotenuse = B₁C/BC ⇒(2)
From (1) and (2)
∴ A₁C/AC = B₁C/BC
using scissors method
∴ A₁C · BC = B₁C · AC
Answer:
31.5 units^2
Step-by-step explanation:
Rectangle area (RA) = l × w
Triangle area (TA) = (bh)/2
RA = 3 × 7
RA = 21
TA = (7 × 3)/2
TA = 21/2
TA = 10.5
(Triangles are congruent as shown by the lines on each side of the triangle so I can calculate area of both of them together as I just did)
Add areas together
21 + 10.5 = 31.5
