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Hitman42 [59]
3 years ago
14

On a coordinate plane, a parabola opens up. Solid circles appear on the parabola at (negative 6, 6), (negative 4. 5, 2. 25), (ne

gative 3, 0), (negative 1. 5, negative 0. 75), (0, 0), (1,5, 2. 25), and (3, 6). Which is the rate of change for the interval between –6 and –3 on the x-axis?.
Mathematics
1 answer:
iragen [17]3 years ago
7 0

The rate of change for the interval between –6 and –3 on the x-axis is -2.

<h2>Given that</h2>

On a coordinate plane, a parabola opens up.

Solid circles appear on the parabola at (-6, 6), (-4. 5, 2. 25), (-3, 0), (-1. 5, -0. 75), (0, 0), (1,5, 2. 25), and (3, 6).

<h3>We have to determine</h3>

Which is the rate of change for the interval between –6 and –3 on the x-axis?

<h3>According to the question</h3>

On a coordinate plane, a parabola opens up.

Solid circles appear on the parabola at (-6, 6), (-4. 5, 2. 25), (-3, 0), (-1. 5, -0. 75), (0, 0), (1,5, 2. 25), and (3, 6).

The rate of change for the interval between x = -6 and x = -3 is simply asking you for the slope of the line that connects these 2 coordinates.

Then,

The rate of change for the interval between –6 and –3 on the x-axis is,

\rm Rate \ of \ change = \dfrac{y_2-y_1}{x_2-x_1}\\&#10;\\&#10; Rate \ of \ change = \dfrac{-6-0}{-3-(-6)}\\&#10;\\&#10; Rate \ of \ change =\dfrac{-6}{3}\\&#10;\\&#10; Rate \ of \ change =-2

Hence, the rate of change for the interval between –6 and –3 on the x-axis is -2.

To know more about Parabola click the link given below.

brainly.com/question/16549411

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Lucy earns ​$5.50 per hour at a local restaurant. She earns time and a half for each hour she works on a holiday. Lucy worked se
Mrrafil [7]
X will be used for the value of money she earned that week.

H represents the normal hours she worked.

D represents the number of days.

Y will represent the hours on the holiday.

Since she would be getting time and a half on the holiday, you would need to find how much time and a half pay would be first.

Time and a half = 5.50(1/2) + 5.50 = $8.25/hr for the day or holiday only.

X = 5.50(H)(D) + 8.25(Y)

Plug in your numbers

X = 5.50(7)(5) + 8.25(4)

X = 192.5 + 33

She made $225.5 that week.
5 0
3 years ago
Find number a and k so that x-2 is afactor<br>OF F(x)=x4-2ax tax-<br>X+k and F(-1)=3​
Slav-nsk [51]

Question:

Find numbers a and k so that x-2 is a factor of

f(x)=x^4-2ax^3+ax^2- x+k

and

f(-1)=3

Answer:

k = -2 and a=1

Step-by-step explanation:

Given

f(x)=x^4-2ax^3+ax^2- x+k

Factor:\ x - 4

f(-1)=3

Required

Find a and k

For f(-1)=3

Substitute -1 for x

f(x)=x^4-2ax^3+ax^2- x+k

f(-1) = (-1)^4 - 2a *(-1)^3 + a*(-1)^2 - (-1) + k

f(-1) = 1 - 2a *-1 + a*1 +1 + k

f(-1) = 1 +2a + a +1 + k

f(-1) = 2 +3a + k

Substitute 3 for f(-1)

3 = 2 +3a + k

Collect Like Terms

3 - 2 = 3a + k

1 = 3a + k

Also:

If x - 2 is a factor, then

f(2) = 0

Substitute 2 for x and 0 for f(x)

f(x)=x^4-2ax^3+ax^2- x+k

0 = 2^4 - 2a * 2^3 + a * 2^2 - 2 + k

0 = 16 - 2a * 8 + a * 4 - 2 + k

0 = 16 - 16a + 4a - 2 + k

0 = 16 - 12a - 2 + k

Collect Like Terms

2 - 16 = - 12a + k

-14 = k - 12a

k = 12a - 14

Substitute 12a - 14 for k in 1 = 3a + k

1 = 3a + 12a - 14

1 = 15a - 14

Collect Like Terms

15a = 1 + 14

15a = 15

Solve for a

a = \frac{15}{15}

a=1

Substitute 1 for a in k = 12a - 14

k = 12 * 1 - 14

k = 12 - 14

k = -2

3 0
3 years ago
Estimate and solve 3,836 ÷ 63 = ________. (2 points)<br> 60 r 9<br> 58 r 56<br> 60 r 56<br> 58 r 9
7nadin3 [17]

Answer:

60 r 56

Step-by-step explanation:

6 0
3 years ago
(Pls help me)
Delicious77 [7]

Answer:

\boxed{ \tt{in \:  a  \:  quadratic  \:  equation \: the \: highest \: power \:  is \: 2}} \\ \boxed{ \tt{hence \: she \: was \: not \: correct}}

6 0
3 years ago
I WANT SOLUTION AND EXPLANATION ANSWER IS GIVEN AT LAST!!!
Pavel [41]
<h3><u>Question:</u></h3>

The present ages of Ram and Rehman are in the ratio 8:9. After 5 years, the ratio of their ages will be 9:10. Find their present ages.

<h3><u>Statement:</u></h3>

The present ages of Ram and Rehman are in the ratio 8:9. After 5 years, the ratio of their ages will be 9:10.

<h3><u>Solution:</u></h3>
  • Let the present age of Ram and Rehman be 8x years and 9x years respectively.
  • After 5 years, their ages will be 9x years and 10 years respectively.
  • Therefore, by the problem

\frac{8x + 5}{9x + 5}  =  \frac{9}{10}  \\  =  > 10(8x + 5) = 9(9x + 5) \\  =  > 80x + 50 = 81x + 45 \\  =  > 50 - 45 = 81x - 80x \\  =  > x = 5

  • So, the present age of Ram = 8x years = (8×5) years = 40 years
  • The present age of Rehman = 9x years = (9×5) years = 45 years
<h3><u>Answer:</u></h3>

The present ages of Ram and Rehman are 40 years and 45 years respectively.

3 0
2 years ago
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