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mart [117]
3 years ago
7

Any1 can help me wif q12

Mathematics
1 answer:
xenn [34]3 years ago
8 0
I) HCF - use the smallest powers of each common factors
HCF (A,B) = 2^2 × 3^4 × 5^2

LCM - use the highest powers of each factors
LCM (A,B) = 2^4 × 3^6 × 5^2 × 7^2 × 11^16

ii) Add powers together.
A×B = 2^6 × 3^10 × 5^4 × 7^2 × 11^16
sqrt(A × B)
Divide powers by 2.
sqrt(A × B) = 2^3 × 3^5 × 5^2 × 7 × 11^8

iii) C = 3^7 × 5^2 × 7
Ck = (3^7 × 5^2 × 7) × k
B/c Ck should be a product that is a perfect cube, the powers of the products should be divisible by 3.
(3^7 × 5^2 × 7) × k = 3^9 × 5^3 × 7^3

k = (3^9 × 5^3 × 7^3) / (3^7 × 5^2 × 7)
k = 3^(9-7) × 5^(3-2) × 7^(3-1)
k = 3^2 × 5 × 7^2
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One number is nine more than another number. If the sum of the numbers is 65 find both numbers
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b) 0.0475

c) 0.7938

Step-by-step explanation:

Let's start defining our random variable.

X : ''Thickness (in mm) of ancient prehistoric Native American pot shards discovered in a Hopi village''

X is modeled as a normal random variable.

X ~ N(μ,σ)

Where μ is the mean and σ is the standard deviation.

To calculate all the probabilities, we are going to normalize the random variable X.

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We normalize by subtracting the mean to X and then dividing by standard deviation.

We can find the values of probabilities for Z in a standard normal distribution table.

We are going to call Φ(A) to the normal standard cumulative distribution evaluated in a value ''A''

a)

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