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2 years ago

it is defined as the intersection of two lines;describes a position in space and has no length, width or height

Physics

1 answer:

Ksivusya [100]2 years ago

5 0

Answer:

Could you explain more?

Explanation:

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Why is accuracy important in dodgeball?

____ [38]

Accuracy and power are the only things that matter in dodge ball. If you are not accurate, then your target does not get hit.

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3 years ago

How roofs are lifted off building in tornado?

bekas [8.4K]

Explanation:

As a tornado or other storm system passes over a building, low pressure can tug a roof upward. When those forces surpass the force exerted by the weight of the roof, the structure flies up and is swept away by wind currents..

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3 years ago

The maximum distance which our normal eye can see distinctly is known as _______________

azamat

Answer:

Far point.

Explanation:

The maximum distance up to which the normal eye can see objects distinct and clear is called the far point of the eye. It is infinity for a normal eye.

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2 years ago

Diagram shows the velocity time graph for a particle moving in 16 seconds.

Leya [2.2K]

Answer:

The detailed calculations are shown below;

Explanation:

a)The maximum acceleration of the particle:

It is seen that the maximum change in velocity is at the time between 8s to 10s.

Maximum acceleration: $\frac{V}{t}$

= $\frac{20}{2}$

= 10 m/ $s^{2}$

b) The deceleration of the particle

The velocity of particle is decreased after 10s so,

deceleration = - $\frac{40}{6}$

= - 6.67 m/ $s^{2}$

c)The total distance traveled by the particle = Area under the curve

= $\frac{1}{2}$ * 4*20 + 4*20 + $\frac{1}{2}$ * 2*20+ 2*20+ $\frac{1}{2}$ * 40*16

= 290 m

d)The average velocity of the particle = $\frac{Area under the curve}{Total time}$

= $\frac{290}{16}$

= 18.12 m/s

3 0

3 years ago

Using a scale of 1 cm to represent 10 N, find the size and direction of the resultant of forces of 50 N

marta [7]

Answer:

$74.31\ \text{N}$

$16.59^{\circ}$

Explanation:

P = 50 N

Q = 30 N

$\theta$ = Angle between the vectors = $45^{\circ}$

Resultant is given by

$R=\sqrt{P^2+Q^2+2PQ\cos\theta}\\\Rightarrow R=\sqrt{50^2+30^2+2\times 50\times 30\times \cos45^{\circ}}\\\Rightarrow R=74.31\ \text{N}$

Angle of resultant

$\phi=\tan^{-1}\dfrac{Q\sin\theta}{P+Q\cos\theta}\\\Rightarrow \phi=\tan^{-1}\dfrac{30\times \sin45^{\circ}}{50+30\cos45^{\circ}}\\\Rightarrow \phi=16.59^{\circ}$

Magnitude of the resultant is $74.31\ \text{N}$

Direction of the resultant is $16.59^{\circ}$

4 0

3 years ago