All categories

3 years ago

When an object experiences uniform circular motion the direction of the net force is?

1 answer:

3 0

In an uniform circular motion, the direction of the net force on the object is radially inward, passing through the center of the circle.

You might be interested in

I have about 4 questions can anyone help? Its about motion (I don't quite know what type of science that is...)

Neko [114]

Motion is physics. motion is the displacement,distance,velocity, acceleration, time, and speed.

6 0

3 years ago

The strength of an electromagnet CANNOT be increased by?

zmey [24]

Answer:

reversing the current

Explanation:

4 0

3 years ago

An infinite plane of charge has a surface charge density of 5 µC/m2 . How far apart are the equipotential surfaces whose potenti

Lostsunrise [7]

Answer:

Distance in mm will be 0.3718 mm

Explanation:

We have given charge surface charge density $\rho _s=5\mu c/m^2=5\times 10^{-6}\mu c/m^2$

We know that electric field due to surface charge density is given by

$E=\frac{\rho _S}{2\epsilon _0}=\frac{5\times 10^{-6}}{2\times 8.85\times 10^{-12}}=2.824\times 10^5Volt/m$

We have given potential difference V = 105 volt

We know that potential difference is given by $V=Ed$

So $105=2.824\times 10^5\times d$

$d=37.181\times 10^{-5}m=0.3718mm$

8 0

3 years ago

A common cylindrical copper wire used in a lab is 841 m long. Find the radius (in mm) of a wire necessary to have 0.5 Ohms of re

slava [35]

The relationship between the resistance R of a wire and its resistivity $\rho$ is given by
$R= \frac{\rho L}{A}$
where L is the length of the wire and A is its cross sectional area.

In the problem, we have $R=0.5 \Omega$ , $\rho = 1.68 \cdot 10^{-8} \Omega m$ and $L=841 m$ . So we can solve the find the area A:
$A= \frac{\rho L}{R}=2.83 \cdot 10^{-5} m^2$

For a cylindrical wire, the cross sectional area is given by
$A= \pi r^2$
where r is the radius. We know the value of the area A, so now we can find the radius of the wire:
$r= \sqrt{ \frac{A}{\pi} }= \sqrt{ \frac{2.83 \cdot 10^{-5}m^2}{\pi} }=0.003 m=3.0 mm$

3 0

3 years ago

3. Two cyclists that are 500 m apart start biking toward each other. They bike at speeds of 6 and

Veronika [31]

Answer:

A) 50 seconds

B) 200 m

Explanation:

They are 500 metres apart.

And one of the bike loves at 6 m/s while the other loves at 4 m/s.

A) Let distance of the 6 m/s bike before they meet be x.

Thus, time = x/6

Since time = distance/speed

For the second bike at 4 m/s, his distance covered before they meet will be 500 - x

Thus, time = (500 - x)/4

Now they will meet each other at the same time. Thus;

x/6 = (500 - x)/4

Cross multiply to get;

4x = 3000 - 6x

6x + 4x = 3000

10x = 3000

x = 3000/10

x = 300 m

Thus, time will be;

t = 300/6

t = 50 seconds

B) Distance covered by the slower bike is (500 - x)

Since from a above, x = 300

Thus; distance = 500 - 300 = 200 m

4 0

3 years ago