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3 years ago

Can someone help me pls

Mathematics

1 answer:

kirill [66]3 years ago

3 0

Answer:

25 ÷ 20

Step-by-step explanation:

The fraction is for divided (÷)

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I need help,plss:(

Andru [333]

Answer:

Step-by-step explanation:

$y=\sqrt{x-1} +4$

graph is shifted right 1 unit and 4 units up.

6 0

3 years ago

Which confidence level would produce the widest interval when estimating the mean of a population based on the mean and standard

Dvinal [7]

<h3>Answer: A) 99%</h3>

Explanation:

The larger the confidence level, the wider the confidence interval gets. Choice A provides the largest such confidence level.

It's like trying to catch an elusive fish. The wider the net, the more confident that you are likely to catch the fish. The size of the net can be a sort of measure of the confidence level.

4 0

2 years ago

Read 2 more answers

Over which interval is the graph of the parent absolute value function f(x) = |xl decreasing?

Romashka [77]

Answer:

(-∞,0)

Step-by-step explanation:

Graph y=|x|

Note that the graph is shaped like a V. The left half of the graph is decreasing from -∞ up until 0 when it hits the origin and starts to increase. Put this into interval notation: (-∞,0).

8 0

4 years ago

Read 2 more answers

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

Estimate the answer by rounding to the nearest tenth<br> 3.07442 + 1.352

Aliun [14]

3.10+1.40= 4.50 nearest tenth

7 0

3 years ago