Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1). The triangle is translated 3 units to the left and 1 unit up. What are
2 answers:
The coordinates of point B' are (-3, 6).
<h2>Given that</h2>Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).
The triangle is translated as 3 units to the left and 1 unit up.
<h3>We have to determine</h3>What are the coordinates of B' after the translation?
<h3>According to the question</h3>Triangle ABC has vertices A(4, 5), B(0, 5), and C(3, –1).
The triangle is translated as 3 units to the left and 1 unit up.
To find the coordinates of B', we will shift the x-coordinate of point B to left by 3 units and the y-coordinate of point B to 1 unit up.
After the given transformation the coordinates of point B' would be:
Therefore, the coordinates of point B' are (-3, 6).
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