Since there are 2 black suites and there are 26 (1/2) black cards in a deck, and there is 1 five per suite, there are 2 black fives. Therefore, since there are 52 cards in a deck, there is a 2/52 you draw a black 5. To find the odds against that, we get 1-2/52=52/52-2/52=50/52 due to that we want to find the probability of not drawing a black 5 so we subtract the chances of getting that from the equation
To find our solution, we can start off by creating a string of 27 boxes, all followed by the letters of the alphabet. Underneath the boxes, we can place 6 pairs of boxes and 15 empty boxes.The stars represent the six letters we pick. The empty boxes to the left of the stars provide the "padding" needed to ensure that no two adjacent letters are chosen. We can create this -

Thus, the answer is that there are

ways to choose a set of six letters such that no two letters in the set are adjacent in the alphabet. Hope this helped and have a phenomenal New Year!
<em>2018</em>
Answer:
When a point is reflected across the y-axis, the y-coordinate(s) remain the same. But the x-coordinate(s) is transformed into opposite signs.
Answer: this is hard I hate math sorry
Step-by-step explanation:
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Step-by-step explanation: