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3 years ago

Encuentra en cada producto notable el error o errores,enciérralo y escribe el resultado correcto.

Mathematics

1 answer:

lbvjy [14]3 years ago

8 0

Given:

The equation is:

$(2x+3y)(2x-3y)=4x^2+6y^2$

To find:

The error in the given equation and correct it.

Solution:

We have,

$(2x+3y)(2x-3y)=4x^2+6y^2$

Taking left-hand side, we get

$L.H.S.=(2x+3y)(2x-3y)$

$L.H.S.=(2x)^2-(3y)^2$ $[\because a^2-b^2=(a-b)(a+b)]$

$L.H.S.=(2)^2(x)^2-(3)^2(y)^2$ $[\because (ab)^x=a^xb^x]$

$L.H.S.=4x^2-9y^2$

It is not equal to right-hand side $4x^2+6y^2$ . In the right hand side, there must be a negative sign instead of positive sign.

Therefore, $(2x+3y)(2x-3y)=4x^2-6y^2$ .

You might be interested in

Write the slope-intercept form of the equation for the line that passes through the point (-1,3) and has a slope of 5/3

cricket20 [7]

Answer:

$y=\frac{5}{3}x+4\frac{2}{3}$

Step-by-step explanation:

slope-intercept form: y = mx + b

Given:

Slope(m) = $\frac{5}{3}$

Point = (-1, 3)

To write the equation in slope-intercept form we need to know the slope(m) and the y-intercept(b). Since we already know the value of m, we can use it and the given point to find b:

$3=\frac{5}{3}(-1)+b$

$3=-\frac{5}{3}+b$

$4\frac{2}{3}=b$

Now that we know the values of b and m, we can write the equation:

$y = \frac{5}{3}x+4\frac{2}{3}$

4 0

3 years ago

PLEASE HELP ME ANSWER! im so desperate bro !!

sergey [27]

a)13

b) skewed

c) IQR

d)Sam's observation is correct

e)6.17

Step-by-step explanation:

Step 1 :

From the histogram we can infer that

0 to 2 texts has been sent by 1 student

2 to 4 texts has been sent by 3 student

4 to 6 texts has been sent by 4 student

6 to 8 texts has been sent by 4 student

8 to 10 texts has been sent by 5 student

Step 2:

From step 1 , we can see that there are total of 17 students represented by the histogram

Step 3:

This is a skewed histogram because we have all large values of students on the right of the histogram and smaller values on the left of the histogram.

In symmetrical histogram, there would be large values on the center and the smaller values on both sides.

Step 4:

IQR would be better recommendation for this as this is a skewed histogram

Standard deviation would be recommended for a symmetrical histogram

Step 5:

Total number of students is 17

Number of students who text between 8 to 10 messages is 5

Hence the students who text between 8 and 10 messages is 5/17

which is nearly 1/3 rd of the total students.

Hence Sam's observation is correct

Step 6:

Mean amount of the texts = (1 * 3 + 3* 3 + 5*4 +7*4 + 9* 5) /17 = 6.17

6 0

3 years ago

What is the slope of y=-4?

aalyn [17]

Answer:

m=0

Step-by-step explanation:

The slope is m=0 and the Y intercept should be b= -4 .

3 0

3 years ago

Read 2 more answers

20 points!!!!!!!

castortr0y [4]

See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid

we know that
One edge of the cuboid has length 2 cm-----> I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1

[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]

100=2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0

using a graph tool------> to resolve the second order equation
see the attached figure

the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm

Find the length of a diagonal of the cuboid
diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm

the answer is
the length of a diagonal of the cuboid is 13.75 cm

4 0

3 years ago

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$