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ZanzabumX [31]
3 years ago
11

Eric randomly surveyed 150 adults from a certain city and asked which team in a contest they were rooting​ for, either north hig

h school or south high school. from the results of his​ survey, eric obtained a​ 95% confidence interval of​ (0.52,0.68) for the proportion of all adults in the city rooting for north high. what proportion of the 150 adults in the survey said they were rooting for north high​ school?

Business
2 answers:
max2010maxim [7]3 years ago
6 0
Interval at 95% confidence = p+/- Z sqrt (p(1-p)/n)
Upper interval => 0.68=p+1.96 sqrt (p(1-p)/n)
Lower interval => 0.52=p-1.96 sqrt (p(1-p)/n)
Putting sqrt term to be "q"

0.68=p+1.96q
0.52=p-1.96q

Adding the two equations to solve for p (proportion of 150 adults rootng for North high school);
1.2 = 2p => p=0.6
Dovator [93]3 years ago
6 0

Answer:

0.60

Explanation:

Please see attachment

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