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2 years ago

it's not homework but can someone tell me if this printer is only for photos or it's just a normal printer

Mathematics

2 answers:

kenny6666 [7]2 years ago

6 0

For photos im pretty sure

tangare [24]2 years ago

3 0

Answer:

It is a normal Printer

Step-by-step explanation:

I Know it because I use it every 10 minutes!

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Please show work need help

Lorico [155]

Step-by-step explanation:

volume of cube=l³

=(11)³

=1331m³

volume of cuboid=l*b*h

=11*8*4

=352m³

6 0

2 years ago

The half-life of a radioactive isotope is the time it takes for a quantity of the isotope to be reduced to half its initial mass

krok68 [10]

So, 0.5^5 is 0.03125
multiply that by 125 and get your answer.
*3.90625* (4)
just saying, I got the 0.5^5 thing because 5 is the number of half-lives (x) and 0.5 is the rate of loss (or whatever its called).
If it were to gain, you would put 1.5

7 0

3 years ago

M% of n? Meaning that you won't get an actual number. For example, m/100*n.

allochka39001 [22]

Answer:

$\frac{m \times n}{100}$

Step-by-step explanation:

The value in $100=m$

The value in $1=\frac{m}{100}$

The value in $n=\frac{m \times n}{100}$

7 0

2 years ago

dele took 25 minutes to walk to school and he arrived at exactly 8:00am, at what time did he leave his home

Roman55 [17]

I think it would be around 7:30am

4 0

2 years ago

Solve the equation below using a graphing

UNO [17]

Answer:

Step-by-step explanation:

The given equation is:

$e^x-\ln 2x = 3.7$

Moving all terms to the left side:

$e^x-\ln 2x - 3.7=0$

Now we define a function:

$y=f(x)=e^x-\ln 2x - 3.7$

The solutions of the equation are the values of x such that y=0.

Since the function cannot be solved by algebraic methods, we use a graphing tool.

Those points where the graph crosses the x-axis are solutions of the equation.

Please refer to the graph in the figure below.

We can clearly identify there are two solutions at

x = 0.05

x = 1.57

6 0

2 years ago

it's not homework but can someone tell me if this printer is only for photos or it's just a normal printer​

it's not homework but can someone tell me if this printer is only for photos or it's just a normal printer