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iren2701 [21]
3 years ago
15

HELP please I need to finish it before midnight.

Mathematics
1 answer:
Blizzard [7]3 years ago
5 0

Answer:

x=-\frac{9ln(15)}{2ln(11)-ln(15)}

Step-by-step explanation:

11^{-2x}=15^{x+9}

e^{(-2x)ln(11)}=e^{(x+9)ln(15)

-2xln(11)=(x+9)ln(15)

-2xln(11)=xln(15)+9ln(15)

-2xln(11)-xln(15)=9ln(15)

x(-2ln(11)-ln(15))=9ln(15)

x=\frac{9ln(15)}{-2ln(11)-ln(15)}

x=-\frac{9ln(15)}{2ln(11)-ln(15)}

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