Find the integer values of x that satisfy both of these inequalities.
2 answers:
Answer:
x ∈ [-2/3, 3)
Step-by-step explanation:
5 − 3x ⩽ 7 and 4x + 1 < 13, this is given
-3x ≤ 7-5 and 4x < 13 -1, subtract 5 from first inequality and subtract -1 from second
-3x ≤ 2 and 4x < 12, combine like terms
x ≥ -2/3 and x < 12/4, divide by -3 and change the first inequality, and divide the second inequality by 4
x ≥ -2/3 and x < 3
[-2/3, ∞) and (-∞, 3)
x ∈ [-2/3, 3)
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Hope this helps you!!!
Answer:
a) x =3 and x=5
c) x =-1 and
i) x =0 and
Step-by-step explanation:
a)
Given that the quadratic equation
x² - 8x +15 =0
The factors of 15 = 5 × 3
x² - 5x -3x +15 =0
x(x -5) -3(x-5) =0
(x-3)(x-5) =0
x =3 and x=5
c)
3 x² + 10 x +7 =0
⇒ 3x² + 3x + 7x +7 =0
⇒ 3x (x +1) +7(x+1) =0
⇒ (x+1) ( 3 x +7) =0
⇒ x =-1 and
i)
2 x ² + 9 x =0
⇒ x( 2 x + 9) =0
⇒ x =0 and 2 x = -9
⇒ x =0 and