Find the integer values of x that satisfy both of these inequalities.
2 answers:
Answer:
x ∈ [-2/3, 3)
Step-by-step explanation:
5 − 3x ⩽ 7 and 4x + 1 < 13, this is given
-3x ≤ 7-5 and 4x < 13 -1, subtract 5 from first inequality and subtract -1 from second
-3x ≤ 2 and 4x < 12, combine like terms
x ≥ -2/3 and x < 12/4, divide by -3 and change the first inequality, and divide the second inequality by 4
x ≥ -2/3 and x < 3
[-2/3, ∞) and (-∞, 3)
x ∈ [-2/3, 3)
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Answer:
Step-by-step explanation:
The equation shown in the question can be seen graphed in the image attached below. As you can see with the graphed equation the variable x can be any real number except for -1. This is because a -1 would cause the denominator of the fraction to be equal to 0, and a fraction with a denominator as 0 is a null value and does not exist.
