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alex41 [277]
3 years ago
5

*50pts* TIMED TEST PLEASE HELP, WILL MAKE BRAINLIEST

Mathematics
2 answers:
shepuryov [24]3 years ago
8 0
5x^4 - 37x^3 - 6x^2 + 41x - 6
mario62 [17]3 years ago
6 0

Answer: The <u>real</u> answer

5x^4-37x^3-6x^2+41x-6

Step-by-step explanation: Go to math

way dot com, enter the equation and it automatically simplifies.


You might be interested in
What is the equation to a graph with the vertex -1,3 and zeros -4 and -2
Mashutka [201]

Answer:

f(x)=x^2+6x+8

Step-by-step explanation:

We are given zeros as x=-4, x=-2

so, we can set up function as

f(x)=a(x+4)(x+2)

Vertex is at (-1,3)

It means that graph passes through point (-1,3)

so, we can plug x=-1 and f(x)=3

and then we can solve for 'a'

3=a(-1+4)(-1+2)

we get

a=1

now, we can plug it back

and we get

f(x)=1(x+4)(x+2)

now, we can simplify it

f(x)=x^2+6x+8

5 0
3 years ago
Which ordered pair is in Quadrant III?
Scilla [17]
(-2,-3) 
I. (+,+)
II. (-,+)
III. (-,-)
IIII. (+,-)
4 0
3 years ago
Please solve this question asap
disa [49]

Step-by-step explanation:

y =  \sqrt{4x + 6}

{y}^{2}  = 4x + 6

{y}^{2}  - 6 = 4x

\frac{1}{4} ( {y}^{2}  - 6) = x

Swap x and y

\frac{ {x}^{2} - 6 }{4}  = y

3 0
2 years ago
Can you guys please help me?! it’s due tomorrow and i don’t know the answers :(
Vlada [557]

Answer:

I think it is the second one because -4 is the least

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
In a sample of 42 water specimens taken from a construction site, 26 contained detectable levels of lead. Construct 90% confiden
hram777 [196]

Answer:

(0.4958, 0.7422)

Step-by-step explanation:

Let p be the true proportion of water specimens that contain detectable levels of lead. The point estimate for p is \hat{p}=26/42=0.6190. The estimated standard deviation is given by \sqrt{\hat{p}(1-\hat{p})/n}=\sqrt{(0.6190)(1-0.6190)/42}=0.0749. Because we have a large sample, the 90% confidence interval for p is given by 0.6190\pm z_{0.05}0.0749 where z_{0.05}=1.6448 is the value that satisfies that above this and under the standard normal density there is an area of 0.05. So, the confidence interval is 0.6190\pm (1.6448)(0.0749), i.e., (0.4958, 0.7422).

5 0
3 years ago
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