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ad-work [718]
3 years ago
6

Ok here we go plz help me

Mathematics
1 answer:
Pepsi [2]3 years ago
5 0

Answer:

I don't have much time cause Zoom is gonna start but the answer to 8 is <u><em>B</em></u>

Step-by-step explanation:

The answer is <em>B</em> because since it's a triangle it will always add up to 180.

Triangles= 180 always

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Please help! Need answer to number 4
alekssr [168]

Answer: H, 1/21

Step-by-step explanation:

7 letters in October

1 b / 7 letters

2 o / 6 letters

1/7 * 2/6 = 2/42 = 1 / 21

5 0
3 years ago
Someone plz answer this for me
padilas [110]
Cos theta = base /perp = sqrt(13)/7 =0.515
4 0
3 years ago
Root 3 cosec140° - sec140°=4<br>prove that<br><br>​
Lorico [155]

Answer:

Step-by-step explanation:

We are to show that \sqrt{3} cosec140^{0} - sec140^{0} = 4\\

<u>Proof:</u>

From trigonometry identity;

cosec \theta = \frac{1}{sin\theta} \\sec\theta = \frac{1}{cos\theta}

\sqrt{3} cosec140^{0} - sec140^{0} \\= \frac{\sqrt{3} }{sin140} - \frac{1}{cos140} \\= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\

From trigonometry, 2sinAcosA = Sin2A

= \frac{\sqrt{3}cos140-sin140 }{sin140cos140} \\\\=  \frac{\sqrt{3}cos140-sin140 }{sin280/2}\\=  \frac{4(\sqrt{3}/2cos140-1/2sin140) }{2sin280}\\\\= \frac{4(\sqrt{3}/2cos140-1/2sin140) }{sin280}\\since sin420 = \sqrt{3}/2 \ and \ cos420 = 1/2  \\ then\\\frac{4(sin420cos140-cos420sin140) }{sin280}

Also note that sin(B-C) = sinBcosC - cosBsinC

sin420cos140 - cos420sin140 = sin(420-140)

The resulting equation becomes;

\frac{4(sin(420-140)) }{sin280}

= \frac{4sin280}{sin280}\\ = 4 \ Proved!

3 0
3 years ago
Martin wants to use coordinate geometry to prove that the opposite sides of
romanna [79]

The correct answer is option A which is the distance between A and D will be  AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

<h3>What is coordinate geometry?</h3>

A coordinate plane is a 2D plane which is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

The formula utilised to find the distance between two points is;-

X = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

We have the coordinates of the point A = (0, 0) and D is  (0, b).By applying the formula to find the distance between A and D.

AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

Therefore the correct answer is option A which is the distance between A and D will be  AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

To know more about Coordinate geometry follow

brainly.com/question/18269861

#SPJ1

4 0
2 years ago
Show that the equation of the line passes (3,5) and (3,-7). Is it possible to what an equation of the line in slope-intercept fo
vodomira [7]

Answer: you need a x and y axis to get this answer

Step-by-step explanation: first you put the (3,5) and (3,-7) in a graph paper then make an y and x axis and you will be able to see your answer visually

5 0
3 years ago
Read 2 more answers
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