Answer:
The answer could be anything, but if it's an arithmetical sequence, then it's 14.
Step-by-step explanation:
I'm assuming that the added numbers always stay the same, meaning it's linear. If you add 5 to 9, you get 14. If you add 5 again, you get 19. Another way of doing this is (19-9)/2 = 5, then 9+5=14.
Step-by-step explanation:
Hey there!
The equation, of a st. line that passes through point (5,9) is,
Put the values,
It is 1st equation.
Now, another equation is,
y = 3x-1.........(ii)
Comparing the equation with y = mx+c.
Slope (m2)= 3
As per the parallel lines,
m1=m2=3
Putting,
the value of m1 in equation(i)
(y-9)= 3(x-5)
y-9= 3x - 15
y = 3x - 6.
So, Krista equation is correct.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
Answer:
StartFraction 50 miles Over 1 hour EndFraction = StartFraction 200 miles Over question mark hours EndFraction
Step-by-step explanation:
For constant speed, miles and hours are proportional. One possible equation is ...
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<em>Comment on the solution</em>
I personally like to put the unknown in the numerator, so the equation can be solved in one step. The equation above requires two steps: one to cross-multiply, and one to divide by 50.
I might write the equation as ...
(? hours)/(200 mi) = (1 hour)/(50 mi) . . . . multiply by 200 mi to solve
Another way to write the equation is matching the ratios of times to corresponding miles:
(? hours)/(1 hour) = (200 mi)/(50 mi)
This only requires simplification to solve it: ? = 4.
In the triangle, the fact that wee are given 2AX = 3XD isn't enough to prove similarity.
<h3>How to explain the triangle?</h3>
a. In the question, we are given 2AX = 3XD. An arbitrary triangle AXB can be drawn where one extends AX and choose a point D on the extended line in order for 2AX = 3XD. Also, extend BX and choose a point C on the line so that 2BX = XC. Even though they both satisfy the condition, they're not similar.
b. We are given that AX/BX = DX/CX. When this is rearranged, we'll have AX/DX = BX/CX. In this case, let AX/DX = k. DX and AX will align upon rotation of 180°. The triangle can then be dilated by a factor of k. This brings about the mapping of triangle DXC to AXB. Therefore, the original triangle DXC is similar to AXB.
c. Lines AB and CD are parallel. Here, the dilation moves line CD onto line AB. Here, since the dilation moves D to a point on ray XA, D must move to A. Therefore, the rotation of triangle DXC is similar to AXB. Therefore, DXC is similar to AXB.
d. Here, angle XAB is congruent to angle XCD. This shows similarity and in this case, XCD is similar to XAB.
Learn more about triangles on:
brainly.com/question/28021872
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