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Assoli18 [71]
3 years ago
6

Write in expanded form 51.242.​

Mathematics
1 answer:
lord [1]3 years ago
3 0

Answer:

50 + 1 + \frac{2}{10} + \frac{4}{100} + \frac{2}{1,000}

Step-by-step explanation:

This is the answer because:

1) 50 and 1 equal to 51

2) The fraction forms of a decimal number is: the decimal number/the decimal number place value

3) Therefore, the answer is 50 + 1 + \frac{2}{10} + \frac{4}{100} + \frac{2}{1,000}

Hope this helps!

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The first term in a geometric series is 64 and the common ratio is 0.75. Find the sum of the first 4 terms in the series.
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Answer:

195.25

Step-by-step explanation:

Consider geometric series  S(n) where initial term is a

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Factor out a

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Multiply by r

S(n)r=a(r+r^2+r^3...+r^n+r^n+1)

Subtract S(n) from S(n)r

Note that only 1 and rn^1 remain.

S(n)r-S(n)=a(r^n+1  -1)

Factor out S(n)

S(n)(r-1)=a(r^n+1  -1)

The formula now shows S(n)=a(r^n+1  -1)/(r-1)

Now use the formula for the problem

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Derek found a function that approximately models the population of iguanas in a reptile garden, where x represents the number of
serious [3.7K]

Answer:

i(x)=12 \times (1+\frac{0.9}{12})^{12x} and growth rate factor is 0.075

Step-by-step explanation:

The function that models the population of iguanas in a reptile garden is given by i(x)=12 \times (1.9)^{x}, where x is the number of years.

Since, i(x)=12 \times (1.9)^{x}

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Therefore, the monthly growth rate function becomes,

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i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Hence, the monthly growth rate is i.e. i(x)=12 \times (1+\frac{0.9}{12})^{12x}.

Also, the growth factor is given by \frac{0.9}{12} = 0.075.

Thus, the growth factor to nearest thousandth place is 0.075.

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