Answer:
Step-by-step explanation:
<em>See the drawing attached</em>
<h3>Given</h3>
- C is midpoint of AB
- B is between A and D
- AD = 15
- BD = 7
- Find CD
<h3>Solution</h3>
- CD = CB + BD =
- 1/2AB + BD =
- 1/2(AD - BD) + BD =
- 1/2(15 - 7) + 7 =
- 1/2(8) + 7 =
- 4 + 7 =
- 11
The sum of interior angles of any polygon is:
s=180(n-2)
Since we are dealing with a triangle:
s=180(3-2)
s=180°
That is, the sum of angles of any triangle is 180°.
In this case we are given two angles with measures of 32° and 102° so
a+b+c=180
32+b+102=180 combine like terms on left
b+134=180 subtract 134 from both sides
b=46°
Answer:
17 hours
Step-by-step explanation:
From the above question,
Anthony is practicing 4 days in a week
Hence
The number of hours he practices in the morning for 4 days =
1.75 hours × 4
= 7 hours
The number of hours he practices in the evening for 4 days =
2.5 hours × 4
= 10 hours
Therefore, the total number of hours he practices this week
= 7 hours + 10 hours
= 17 hours
688
x 29
6192
1376 x
19952
So you start by taking 9 from 29 and multiplying it by 688. when you get the answer put it below the line. then multiply the 2 from the 29 and whne you get the answer put a zero on the end and then add the answer you got from 9x688 (6192) and 2x688 (13760) and then thats youre answer. hope it helps!
Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
