Solution:
1) Rewrite it in the form {a}^{2}-2ab+{b}^{2}, where a={d}^{2} and b=4
{({d}^{2})}^{2}-2({d}^{2})(4)+{4}^{2}
2) Use Square of Difference: {(a-b)}^{2}={a}^{2}-2ab+{b}^{2}
{({d}^{2}-4)}^{2}
3) Rewrite {d}^{2}-4 in the form {a}^{2}-{b}^{2} , where a=d and b=2
{({d}^{2}-{2}^{2})}^{2}
4) Use Difference of Squares: {a}^{2}-{b}^{2}=(a+b)(a-b)
{((d+2)(d-2))}^{2}
5) Use Multiplication Distributive Property: {(xy)}^{a}={x}^{a}{y}^{a}
{(d+2)}^{2}{(d-2)}^{2}
Done!
Answer:
5/10
Step-by-step explanation:
Answer:
The artist used 8.6 inches more of silver wire
Step-by-step explanation:
Perimeter of the square
P = 4*a
P = 4*a = 40 in
a = 10 in
Each side of the square has a length of 10 in
The diameter of the circle is equal to the length of the side of the square
Diameter = 10 in
Perimeter of the circle
P_c = 2*π*radius = π*diameter
P_c = (3.14)*10 in = 31.4 in
Inches of silver wire (square) = 40 in
Inches of copper wire (circle) = 31.4 in
40- 31.4 in = 8.6 in
