Answer:
This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).
Step-by-step explanation:
The given function is 

To find  , we substitute
, we substitute  into the function.
 into the function.



To find  , we substitute
, we substitute  into the function.
 into the function.



To find  , we must first find
, we must first find  .
.

This implies that;





For this function to satisfy the Rolle's Theorem;
It must be continuous on ![[-64,64]](https://tex.z-dn.net/?f=%5B-64%2C64%5D) .
.
It must be differentiable  on  .
.
and 
 .
.
All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.