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a_sh-v [17]
3 years ago
10

What is 5mm as a radius plz help

Mathematics
1 answer:
exis [7]3 years ago
6 0
Well, assuming 5mm is the diameter, then 2.5 mm is the radius.
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The graph below belongs to which function family?
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The answer is the last one (absolute value)
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Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

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3 years ago
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3 years ago
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Advocard [28]
1. find equation

general solutions are:
y = a x^{2} +bx +c \\ \\ \frac{dy}{dx} = 2ax +b

for P(0,-11)

-11 = 0a + 0b +c ⇒c = -11

for p(1,-13)
-13 = 1a + 1b -11 \\ a+b = -2

and

0 = 2a + b \\ b = -2a

solve for a and b:
a - 2a = -2 \\ a = 2 \\ b = -4

the total equation is now:

y = 2 x^{2} -4x -11

To find the x-intercept set y=0 and solve for x

0 = 2 x^{2} -4x-11
4 0
3 years ago
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Tan9°. tan27°. tan45°. tan72°. tan81°= 1​<br><br>could u plz solve it with clear process
Inga [223]

<u>Correct</u><u> </u><u>question</u><u>:</u><u>-</u>

<u>Prove </u><u>that </u><u>tan9.</u><u>t</u><u>a</u><u>n</u><u>1</u><u>7</u><u>.</u><u>t</u><u>a</u><u>n</u><u>4</u><u>5</u><u>.</u><u>t</u><u>a</u><u>n</u><u>7</u><u>3</u><u>.</u><u>t</u><u>a</u><u>n</u><u>8</u><u>1</u><u>=</u><u>1</u>

<u>LHS</u>

\\ \sf\longmapsto tan9.tan17.tan45.tan73.tan81

\\ \sf\longmapsto tan9.tan81.tan17.tan73.tan45

\\ \sf\longmapsto tan(90-81).tan81.tan(90-73).tan73.1

\\ \sf\longmapsto cot81.tan81.cot73.tan73

\\ \sf\longmapsto 1.1

\\ \sf\longmapsto 1

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2 years ago
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