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fgiga [73]
2 years ago
9

if Sarah repaired her computer her bill was 1444.50 dollars and she included a 15 percent gratuity whats her new total cost

Mathematics
1 answer:
tiny-mole [99]2 years ago
7 0
The new cost would be 1661.175 if u want it rounded it would be 1661.18 because you would need to do 1444.5 x .15 and then add that to 1444.5
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3. Rewrite the expression as simply as you can:<br> 3x + 11y - 2x - 4y
vfiekz [6]

Answer:

x+7y

Step-by-step explanation:

First off, lets split the question into both x and y.

3x - 2x for the x

11y - 4y for the y

You can solve both of them to get x + 7y

3x - 2x = x

11y - 4y = 7y

Then, add them back up and get x + 7y

7 0
3 years ago
Read 2 more answers
The slope of a line perpendicular to the line whose equation is y = 3x - 4 is
trapecia [35]

Answer:

m = -1/3

Step-by-step explanation:

y = 3x-4

This is in slope intercept form

y = mx+b  m is the slope and b is the y intercept

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We want the slope of a line that is perpendicular

Perpendicular lines have slopes that multiply to -1

Let m be the slope of the line that is perpendicular

3 * m = -1

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6 0
3 years ago
Please explain how you got your answer (:
melisa1 [442]
I used math

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remember you can do anything to an equation as long as you do it to both sides

so

4n+2 and 1/2=2n+5
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2n+2 and 1/2=0+5
2n+2 and 1/2=5
minus 2 and 1/2 both sides
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6 0
3 years ago
What is the square root of 2x plus the square root of 2x
WITCHER [35]

Answer:

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3 years ago
A transformer increases the input voltage from 12V to 12,000V. What is the ratio of the number of wire turns on the primary coil
erma4kov [3.2K]

Answer:

\frac{n_p}{n_s}=\frac{1}{1000}

Step-by-step explanation:

Given voltage of primary coil is V_p=12V

And voltage of secondary coil is V_s=12,000V

A transformer is a device that contains primary and secondary coil. These coils are mounted on soft iron. The change in voltage depends upon the number of turns of primary coil (n_p) and secondary coil (n_s).

Following equation represents the relation between them.

\frac{V_s}{V_p} =\frac{n_s}{n_p}\\\\\frac{12,000}{12}=\frac{n_s}{n_p}\\\\1000=\frac{n_s}{n_p}

Then, ratio of the number of wire turns on the primary coil to the number of turns on the secondary coil is

\frac{n_p}{n_s}=\frac{1}{1000}

5 0
3 years ago
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