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3 years ago

What is the fraction of 41.66667

Mathematics

2 answers:

Artyom0805 [142]3 years ago

8 0

Answer:

41.66 repeating or 41.67

Step-by-step explanation: hope this helps

Papessa [141]3 years ago

6 0

Answer:

$41\frac{2}{3}$

I hope this helps!

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What the 15th sequence for 4.5n-8

damaskus [11]

Given:
The sequence formula;
Tn = 4.5n - 8 (Where n = term number)

Required:
15th term = ?

Procedure:
All you need to do is use n = 15

T15 = 4.5(15) - 8
T15 = 59.5

Conclusion:
The 15th term of the sequence is 59.5.

5 0

3 years ago

Round 418 to the nearest ten.

marissa [1.9K]

Answer:

The answer should be 420.

Step-by-step explanation:

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2 years ago

(Circumference or circles)<br> explain your answer so I can understand

Ghella [55]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

A line passes through the points (-4,5) and (1,-5). Write the equation of the line in slope-

sweet [91]

Answer:

y = -2x - 3

Step-by-step explanation:

Slope: (5 - - 5)/(-4 -1) = 10/-5 = -2

y-intercept: 5 - (-2)(-4) = -3

4 0

2 years ago

Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti

spayn [35]

Answer:

(a) $D(x)=-2,500x+60,000$

(b) $R(x)=60,000x-2500x^2$

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

$\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500$

Therefore, we have:

$y=-2500x+b$

At point (12,30000)

$30000=-2500(12)+b\\b=30000+30000\\b=60000$

Therefore:

$D(x)=-2,500x+60,000$

(b)Revenue

$R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2$

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

$R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12$

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

$R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0$

Therefore:

Optimal ticket price:$12
Maximum Revenue:$360,000

3 0

3 years ago