Answer:
0.430625 = 0.431
Step-by-step explanation:
Let W represent winning, D represent a draw and L represent a loss.
12+ points can be garnered in each of the following ways.
6W 0D 0L
5W 1D 0L
5W 0D 1L
4W 2D 0L
4W 1D 1L
4W 0D 2L
3W 3D 0L
The probability of getting 12+ points is the sum of all these 7 probabilities.
Knowing that P(W) = 0.5
P(D) = 0.1
P(L) = 0.4
P(6W 0D 0L) = [6!/(6!0!0!)] 0.5⁶ 0.1⁰ 0.4⁰ = 0.015625
P(5W 1D 0L) = [6!/(5!1!0!)] 0.5⁵ 0.1¹ 0.4⁰ = 0.01875
P(5W 0D 1L) = [6!/(5!0!1!)] 0.5⁵ 0.1⁰ 0.4¹ = 0.075
P(4W 2D 0L) = [6!/(4!2!0!)] 0.5⁴ 0.1² 0.4⁰ = 0.09375
P(4W 1D 1L) = [6!/(4!1!1!)] 0.5⁴ 0.1¹ 0.4¹ = 0.075
P(4W 0D 2L) = [6!/(4!0!2!)] 0.5⁴ 0.1⁰ 0.4² = 0.15
P(3W 3D 0L) = [6!/(3!3!0!)] 0.5³ 0.1³ 0.4⁰ = 0.0025
The probability of getting 12+ points = 0.015625 + 0.01875 + 0.075 + 0.09375 + 0.075 + 0.15 + 0.0025 = 0.430625
Volume of a cone = 1/3 π r² h
235.5 = 1/3 (3.14) r² (9)
(3.14) r² (9) = 706.5
r² = 25
r = 5
Answer: Radius = 5 cm
Answer:
The area of the circular ripple after t second is
A =25π t²
where A is in cm².
Step-by-step explanation:
Given that,
Circular ripple that travels outward at a speed of 5 cm per second.
It means that, the radius of the circular ripple increases at a seed 5 cm/ s.
Therefore the radius of the circular ripple after t seconds is
r(t)= 5t
where r(t) is in cm.
We know ,
The area of a circular object is = π r²
The area of the circular ripple after t second is
A= π(5t)²
=25πt²
where A is in cm².
