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tatuchka [14]
3 years ago
11

The Wilsons have triplets and another child who is thirteen years old. The sum of the ages of their children is 37. How old are

the triplets?
Mathematics
2 answers:
BabaBlast [244]3 years ago
7 0
The triplets will be 8 years old because if you subtract 13 to the sum you get 24 and that divided by 3 gives you 8
valentinak56 [21]3 years ago
4 0
The answer is 8 years old.
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-8x+2y=-2<br> 4x+4y=-4<br> What is the solution to the system
pickupchik [31]

The solution to system is x = 0 and y = -1

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

-8x + 2y = -2 ----------- eqn 1

4x + 4y = -4 ---------- eqn 2

We have to solve the system of equations

We can solve the equations by elimination method

<em><u>Multiply eqn 2 by 2</u></em>

8x + 8y = -8 ------ eqn 3

<em><u>Add eqn 1 and eqn 3</u></em>

-8x + 2y = -2

8x + 8y = -8

( + ) ---------------

0x + 2y + 8y = -2 - 8

10y = -10

Divide both sides by 10

y = -1

<em><u>Substitute y = -1 in eqn 1</u></em>

-8x + 2(-1) = -2

-8x - 2 = -2

-8x = -2 + 2

x = 0

Thus the solution to system is x = 0 and y = -1

3 0
3 years ago
​Find all roots: x^3 + 7x^2 + 12x = 0 <br> Show all work and check your answer.
Aliun [14]

The three roots of x^3 + 7x^2 + 12x = 0 is 0,-3 and -4

<u>Solution:</u>

We have been given a cubic polynomial.

x^{3}+7 x^{2}+12 x=0

We need to find the three roots of the given polynomial.

Since it is a cubic polynomial, we can start by taking ‘x’ common from the equation.

This gives us:

x^{3}+7 x^{2}+12 x=0

x\left(x^{2}+7 x+12\right)=0   ----- eqn 1

So, from the above eq1 we can find the first root of the polynomial, which will be:

x = 0

Now, we need to find the remaining two roots which are taken from the remaining part of the equation which is:

x^{2}+7 x+12=0

we have to use the quadratic equation to solve this polynomial. The quadratic formula is:

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Now, a = 1, b = 7 and c = 12

By substituting the values of a,b and c in the quadratic equation we get;

\begin{array}{l}{x=\frac{-7 \pm \sqrt{7^{2}-4 \times 1 \times 12}}{2 \times 1}} \\\\{x=\frac{-7 \pm \sqrt{1}}{2}}\end{array}

<em><u>Therefore, the two roots are:</u></em>

\begin{array}{l}{x=\frac{-7+\sqrt{1}}{2}=\frac{-7+1}{2}=\frac{-6}{2}} \\\\ {x=-3}\end{array}

And,

\begin{array}{c}{x=\frac{-7-\sqrt{1}}{2}} \\\\ {x=-4}\end{array}

Hence, the three roots of the given cubic polynomial is 0, -3 and -4

4 0
3 years ago
for f(x)=1/x-5 and g(x)=x^2+2 find the expression for g(x) and substitute the value of g(x) into the function in place of x to f
IRISSAK [1]

Answer:

f(x)  = (1/x) - 5

g(x) = x^2 + 2

=> f[g(x)] = [1/(x^2 +2)] - 5

5 0
3 years ago
What value of x makes this equation true?
natali 33 [55]

Answer:

-1.8 =x

Step-by-step explanation:

12(x+3)=-8x

Distribute

12x +36 = -8x

Subtract 12x from each side

12x-12x +36 = -8x-12x

36 = -20x

Divide each side by -20

36/-20 = -20x/-20

-9/5 = x

Changing to decimal form

-1.8 =x

4 0
3 years ago
Read 2 more answers
Penjabaran dari 3×+2(4×-6)
DedPeter [7]
3x+2(4x-6)
Distriuthing 2 through parentheses
3x+2*4x-2*6
3x+8x-2*6
3x+8x-12
11x-12
7 0
3 years ago
Read 2 more answers
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