The order of growth execution time of the push operation when using the LinkedStack class, assuming a stack size of N is; O(1)
<h3>Understanding Computer Programming Language</h3>
Let Top be the position of last element inserted in Array.
For Push operation, the process is as follows;
if(Top == last index of Array) {
Printf(“Stack Overflow”)
} else {
Top = Top + 1
a[Top] = element you want to insert
}
Read more about Computer Programming at; brainly.com/question/22654163
1. A script or scripting language is a computer language<span> with a series of commands within a file that is capable of being executed without being compiled.
2. Software development
3. true
4. im not sure
here is a sight that might help
https://quizlet.com/150321269/video-game-design-terms-flash-cards/
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Answer:
Option a. int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }
is the correct code snippet.
Explanation:
Following is given the explanation for the code snippet to find largest value in an integer array list aList.
- From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
- By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
- If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
- When the loop will end, the variable max will have the greatest value from the array aList.
i hope it will help you!
Answer:
<u>Solution a</u>
- n = int(input("Enter an integer: "))
-
- sum = 0
-
- for x in range(1, n+1):
- sum += x
-
- print(sum)
<u>Solution b</u>
- n = int(input("Enter an integer: "))
-
- for a in range(1, n + 1):
- sum = 0
- for x in range(1, a+1):
- sum += x
- print(sum)
Explanation:
Solution code is written in Python 3.
<u>Solution a</u>
First get the user input for an integer (Line 1).
Create a variable sum and initialize it with zero value (Line 3).
Create a for loop to traverse through the number from 1 to integer n (inclusive) and sum up the current number x (Line 5-6).
Print the sum to terminal (Line 8).
<u>Solution b</u>
Create an outer for loop that traverse through the number from 1 to integer n (inclusive) (Line 3).
Create an inner loop that traverse through the number from 1 to current a value from the outer loop and sum up the current x value (Line 5-6).
Print the sum to terminal (Line 7) and proceed to next iteration and reset the sum to zero (Line 4).