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AVprozaik [17]
2 years ago
11

Over the last six months, the following numbers of absences have been reported: 10, 16, 12, 18, 2, and 14. What is the median nu

mber of monthly absences?
Mathematics
1 answer:
nasty-shy [4]2 years ago
5 0

Using it's concept, it is found that the median number of monthly absences is of 13.

The <em>median </em>of a data-set is the <u>value that separates the bottom 50% of the data-set from the upper 50%</u>.

The first step is ordering the data-set, hence:

2, 10, 12, 14, 16, 18

In this problem, the cardinality is of 6, which is a even number.

  • Hence, the median is the <u>mean of the 6/2 = 3rd and 4th elements</u>.

Then:

\frac{12 + 14}{2} = 13

The median number of monthly absences is of 13.

To learn more about the median, you can take a look at brainly.com/question/10322579

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Is w^2-9w+81 a trinomial square
Yuri [45]
No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be
( \sqrt{a}x+ \sqrt{c})^{2} or ( \sqrt{a}x- \sqrt{c})^{2}
so
if w^2-9w+81 is perfect square, factored form is either
( \sqrt{1}x+ \sqrt{81})^{2} or ( \sqrt{1}x- \sqrt{81})^{2}  aka ( x+9)^{2} or  ( x-9)^{2}
expand them
(x+9)^2=x^2+18x+81, wron middle term

(x-9)^2=x^2-18x+81 wrong

so it is not






8 0
3 years ago
How many times does 20 go into 168?
ch4aika [34]
The answer:

8 times

Explanation:

If you divide 168 by 20, you get 8.4, and the whole number is 8 so that’s the answer.
7 0
3 years ago
Read 2 more answers
Find the value of each variable. If you answer is not an integer, express it in simplest rauitar
Marrrta [24]
This is one of the special right triangles known as a 30, 60, 90 triangle. (Characterized by its angles)

In these triangles, the shortest leg is HALF the length of the hypotenuse.

The longest leg is (√3) times the length of the short leg.

Therefore, the shortest leg is 20, and the longest leg is 20(√3)

FINAL ANSWER:

SHORT LEG: 20 units

LONG LEG: 20√3 units
8 0
3 years ago
1.) Find the value of the discriminant and the the number of real solutions of
ruslelena [56]
Hi there!

When we have an equation standard form...
a {x}^{2} + bx + c = 0
...the formula of the discriminant is
D = b^2 - 4ac

When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions

1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0

Plug in the values from the equation into the formula of the discriminant

( - 8) {}^{2} - 4 \times 1 \times 7 = 64 - 28 = 36

D > 0 and therefore we have two real solutions.

2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0

Again, plug in the values from the equation into the formula of the discriminant.

{4}^{2} - 4 \times 2 \times 2 = 16 - 16 = 0

D = 0 and therefore we have one real solution.

~ Hope this helps you.
4 0
2 years ago
Read 2 more answers
Given the right triangle below what is x?
lions [1.4K]

Answer:

B 10.8 or

A 9.2 depending on what side of the triangle is "x".

Step-by-step explanation:

we cannot see the triangle and which side is which. you forgot to show us the picture (or describe it in more detail).

but I assume that "x" would be the Hypotenuse (the baseline of the right triangle, the side opposite of the 90 degree angle).

then by using Pythagoras

c² = a² + b²

=>

x² = 10² + 4² = 116

x = sqrt(116) = 10.8

but if x is any of the other sides (and not the Hypotenuse), then you need to adapt the calculation.

for example, if the Hypotenuse is the side with 10, then Pythagoras' formula would look like this

10² = x² + 4²

x² = 10² - 4² = 84

x = sqrt(84) = 9.2 (and answer A would be correct).

or if the Hypotenuse is the side with 4, then

4² = x² + 10²

x² = 4² - 10² = -84

x = sqrt(-84)

and that did not make any sense for real distances. so, this configuration is actually impossible for a right triangle.

5 0
3 years ago
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