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AVprozaik [17]
3 years ago
11

Over the last six months, the following numbers of absences have been reported: 10, 16, 12, 18, 2, and 14. What is the median nu

mber of monthly absences?
Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

Using it's concept, it is found that the median number of monthly absences is of 13.

The <em>median </em>of a data-set is the <u>value that separates the bottom 50% of the data-set from the upper 50%</u>.

The first step is ordering the data-set, hence:

2, 10, 12, 14, 16, 18

In this problem, the cardinality is of 6, which is a even number.

  • Hence, the median is the <u>mean of the 6/2 = 3rd and 4th elements</u>.

Then:

\frac{12 + 14}{2} = 13

The median number of monthly absences is of 13.

To learn more about the median, you can take a look at brainly.com/question/10322579

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=14bx2−7x3−4b+2x

Step-by-step explanation:

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Write each decimal as a fraction <br> .07<br> .051<br> .473<br> .27<br> .5.37<br> .16.49
Colt1911 [192]

Answer:

7/10

51/100

473/1000

27/100

537/1000

1649/10000

Step-by-step explanation:

im curious about what the dots are in .16.49 and .5.37, why are there two dots?

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2 years ago
What is the arc length S what is shown below?
Solnce55 [7]

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  14 cm

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  s = rθ

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3 0
3 years ago
According to a certain news poll, 71% agreed that it should be the government's responsibility to provide a decent standard of l
finlep [7]

Answer:

0.3157

Step-by-step explanation:

Given that according to a certain news poll, 71% agreed that it should be the government's responsibility to provide a decent standard of living for the elderly,

Let A be the event that it should be the government's responsibility to provide a decent standard of living for the elderly, and B the event that it would be a good idea to invest part of their Social Security taxes on their own

P(B) = 41%=0.41

A and B are independent

Hence P(both)=0.77(0.41) = 0.3157\\

the probability that a person agreed with both propositions

= Probability for both A and B

= P(A) P(B) since A and B are independent

= 0.3157

3 0
3 years ago
A survey of 1 comma 558 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying
sineoko [7]

Answer with explanation:

Let  p be the proportion of adults have heard of the new electronic reader.

Given claim : The accompanying technology display results from a test of the claim that 38​% of adults have heard of the new electronic reader.

i.e. p=0.38

Then , the set of hypothesis will be :-

H_0: p=0.38\\\\H_a:p\neq0.38

Since, the alternative hypothesis is two tailed , so the test is two-tailed test.

Also, it is given that the sample size : n=1558

Number of adults showed that they have heard of a new electronic reader=522

So the sample proportion for adults have heard of the new electronic reader : \hat{p}=\dfrac{522}{1558}\approx0.34



The test statistic for proportion is given by :-

z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\\Rightarrow\ z=\dfrac{0.34-0.38}{\sqrt{\dfrac{0.38(1-0.38)}{1558}}}\\\\\\\Rightarrow\ z=-3.25279036541\approx-3.25

By using standard normal distribution table , the P-value for two tailed test corresponds to the obtained z-value ==0.0011541

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3 years ago
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