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AVprozaik [17]
3 years ago
11

Over the last six months, the following numbers of absences have been reported: 10, 16, 12, 18, 2, and 14. What is the median nu

mber of monthly absences?
Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0

Using it's concept, it is found that the median number of monthly absences is of 13.

The <em>median </em>of a data-set is the <u>value that separates the bottom 50% of the data-set from the upper 50%</u>.

The first step is ordering the data-set, hence:

2, 10, 12, 14, 16, 18

In this problem, the cardinality is of 6, which is a even number.

  • Hence, the median is the <u>mean of the 6/2 = 3rd and 4th elements</u>.

Then:

\frac{12 + 14}{2} = 13

The median number of monthly absences is of 13.

To learn more about the median, you can take a look at brainly.com/question/10322579

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Write the equation of the line that is parallel to y=4x-3 and passes through the point (5,12)
katovenus [111]

Answer

y=4x-8

Step-by-step explanation:

m = 4

y- 12 = 4(x-5)

simplify and keep it in point-slop form

y=4x-8

6 0
3 years ago
-11=a+7 dolce equation
zubka84 [21]

-11 = a + 7   Given

-7        -7    Subtract 7 on each side to cancel out +7 and isolate variable

-18 = a       Answer

Prove.

-11 = -18 + 7    Plug in variable value

-11 = -11

True.

4 0
3 years ago
Read 2 more answers
Mrs. Rivera has bars of chocolate in a box. The total mass of bars of chocolate in the box is 3 kilograms. What is the mass in g
sergeinik [125]

Answer:The chocolate in the box is 3000 grams.

Every Kilogram has 1000 grams

You multiply 1000×3=3000

6 0
3 years ago
Find the measure of line KM.<br> A. 14<br> B. 9<br> C. 12<br> D. 10
HACTEHA [7]

\\ \sf\longmapsto \dfrac{3}{x-4}=\dfrac{6}{x-5}

\\ \sf\longmapsto 3(x-5)=6(x-4)

\\ \sf\longmapsto 3x-15=6x-24

\\ \sf\longmapsto 3x-6x=-24+15

\\ \sf\longmapsto -3x=-9

\\ \sf\longmapsto x=\dfrac{-9}{-3}

\\ \sf\longmapsto x=3

\\ \sf\longmapsto KM=3+6=9

6 0
3 years ago
Please Answers with steps...will be much appreciated!!!
11Alexandr11 [23.1K]
To solve the exercirses which are shown in the figure attached, you must follow the proccedure below:

 7) (x)=x³-6x²+8x
 (x)=x(x³-6x²+8)
 (x)=(x-4)(x-2)x

 The lenght is: x
 The height is= (x-4)

 8) √(2x+8)-6=4

1. You need to clear the variable "x". Then:

 √(2x+8)=4+6
 √(2x+8)=10
 (√2x+8)²=10²
 2x+8=100
 2x=100-8
 x=92/2
 x=46

 9) l4x+3l=9+2x

 1. To solve the left member, you must evaluate two cases: it could be positive,or negative. Then:

 2. Negative:

 l4x+3l=9+2x
 -4x-3=9+2x
 -4x-2x=9+3
 -6x=12
 x=12/-6
 x=-2

 3. Positive:

 l4x+3l=9+2x
 4x+3=9+2x
 4x-2x=9-3
 2x=6
 x=6/2
 x=3
4 0
3 years ago
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