No because it would be
if you knew that
ax^2+bx+c was a trinomial square, then the factored form would be

or

so
if w^2-9w+81 is perfect square, factored form is either

or

aka

or
expand them
(x+9)^2=x^2+18x+81, wron middle term
(x-9)^2=x^2-18x+81 wrong
so it is not
The answer:
8 times
Explanation:
If you divide 168 by 20, you get 8.4, and the whole number is 8 so that’s the answer.
This is one of the special right triangles known as a 30, 60, 90 triangle. (Characterized by its angles)
In these triangles, the shortest leg is HALF the length of the hypotenuse.
The longest leg is (√3) times the length of the short leg.
Therefore, the shortest leg is 20, and the longest leg is 20(√3)
FINAL ANSWER:
SHORT LEG: 20 units
LONG LEG: 20√3 units
Hi there!
When we have an equation standard form...

...the formula of the discriminant is
D = b^2 - 4ac
When
D > 0 we have two real solutions
D = 0 we have one real solutions
D < 0 we don't have real solutions
1.) Find the value of the discriminant and the the number of real solutions of
x^2-8x+7=0
Plug in the values from the equation into the formula of the discriminant

D > 0 and therefore we have two real solutions.
2.) Find the value of the discriminant and the number of real solutions of
2x^2+4x+2=0
Again, plug in the values from the equation into the formula of the discriminant.

D = 0 and therefore we have one real solution.
~ Hope this helps you.
Answer:
B 10.8 or
A 9.2 depending on what side of the triangle is "x".
Step-by-step explanation:
we cannot see the triangle and which side is which. you forgot to show us the picture (or describe it in more detail).
but I assume that "x" would be the Hypotenuse (the baseline of the right triangle, the side opposite of the 90 degree angle).
then by using Pythagoras
c² = a² + b²
=>
x² = 10² + 4² = 116
x = sqrt(116) = 10.8
but if x is any of the other sides (and not the Hypotenuse), then you need to adapt the calculation.
for example, if the Hypotenuse is the side with 10, then Pythagoras' formula would look like this
10² = x² + 4²
x² = 10² - 4² = 84
x = sqrt(84) = 9.2 (and answer A would be correct).
or if the Hypotenuse is the side with 4, then
4² = x² + 10²
x² = 4² - 10² = -84
x = sqrt(-84)
and that did not make any sense for real distances. so, this configuration is actually impossible for a right triangle.