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Flura [38]
3 years ago
9

What is the answer to 13/2x-5/x

Mathematics
2 answers:
horrorfan [7]3 years ago
8 0

Answer:

3/2x

Step-by-step explanation:

13/2x-5/x=3/2x

98% sure it is the answer

Zarrin [17]3 years ago
3 0

Answer:

(13x^2-10)/(2x)    

Step-by-step solution:

STEP 1:

simplify 5/x

(13/2 • x)- 5/x

STEP 2:

simplify 13/2

STEP 3:

find the least common multiple

= 13/2x - 5/x

= 13-2(5)/2x

= 13-10/2x

= 3/2x 

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3 years ago
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OmZC > mZE > m2D
matrenka [14]

Answer:

Step-by-step explanation: Answer to ol in your answer.) What are mZA, mZB, and mZC? mZA= (Round to one decimal place as needed. Do not include the degree. I hope this either gives you a quick hint and a tip. Thank you and have a good day.

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3 years ago
Given that x = 7.4 m and 0 = 26°, work out AB rounded to 3 SF.
Vladimir [108]

Answer:

3.24m

Step-by-step explanation:

SOH

sin(26)=O/7.4

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7 0
3 years ago
Kinda want to cry right now.. Someone PLEASE help me.. I know there is someone out there smart enough.... 25 points and Brainlie
Svetlanka [38]

Answer:

a) Infinite solutions

b) No solutions

Step-by-step explanation:

First, know the following:

If the graphs intersect, there's only one solution.

If the graphs are parallel, there are no solutions.

If the graphs are the exact same line, there are infinite solutions.

For a):

Change the first equation into a linear one.

  • 2x+3y=6
  • 3y=-2x+6
  • y=-\frac{2}{3} x+2

Change the second equation into a linear one.

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  • 6y=-4x+12
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Boom. You have two equations which are equal. As stated above, graphs on the exact same line have infinite solutions.

For b)

They are already in linear form so hurray.

y=\frac{1}{5} x+2\\y=\frac{1}{5} x+10\\

These lines are parallel since they have the SAME slope but a different y-intercept. As stated above, parallel lines have no solutions.

5 0
3 years ago
The cost of a car rental is ​$30 per day plus 18c per mile. You are on a daily budget of ​$75. Write and solve an inequality to
Tanzania [10]

Answer:

2. 5 miles

Step-by-step explanation:

Given that:

Rental cost = $30

Cost per mile driven = 18 cent

Daily budget = $75

Greatest distance you can drive each day while staying within budget :

Rental cost + (cost per mile driven * distance) ≤ daily budget

$30 + 18d ≤ $75

18d ≤ 75 - 30

18d ≤ 45

d ≤ 45 / 18

d ≤ 2.5

Greatest distance you can drive each day while staying within budget is 2.5 miles.

8 0
3 years ago
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