Pretty sure it’s B not 100% tho
Answer:
d. 99.63% and 0.364%, respectively
Explanation:
The average mass of a nitrogen atom is 14.006 amu
14N-14.00307 amu with 0.9963 fractional abundance
1SN- 15.000108 amu with 0.00364 fractional abundance.
The relative abundance definition in chemistry is the percentage of a particular isotope that occurs in nature. The atomic mass listed for an element on the periodic table is an average mass of all known isotopes of that element.
In this problem, the fractional abundance has areaady been given. All we need to do now is convert them to percentage abundance.
14N-14.00307 = 0.9963* 100% = 99.63%
1SN- 15.000108 = 0.00364 * 100% = 0.364%
Answer: 27.27%
Mass percentage of carbon in carbon dioxide is 4412×100=27. 27%.
Answer:
Fe: 23.1%
N: 17.4%
O: 59.5%
Explanation:
You take the grams that each weigh on the periodic table and add it all up. Afterward you create fractions of each over the whole. (Example: Fe/Fe+N+O) then you divide and turn that decimal into a percentage.
Answer:
c. carbon monoxide
Explanation:
no one bothers to read why anyways so look at the picture
