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3 years ago

Why the mixture should not be strongly heated during sublimation

Chemistry

1 answer:

daser333 [38]3 years ago

6 0

Answer:

because strong heated makes temperatures and pressures reach the substance's triple point in its phase diagram, So the substance can be in a liquid case , and that is against the sublimation process meaning

which define as the transition of a matter or a substance from the solid phase to the gas phase directly, without passing through the intermediate liquid phase

sublimation process happens by absorbing of heat which makes molecules overcome attractive force between each other and changing to gas phase

but in the previous case it will pass through the liquid phase so it will not be sublimation process any more

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Calculate the osmotic pressure (in torr) of 6.00 L of an aqueous 0.958 M solution at 30.°C, if the solute concerned is totally i

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<u>Answer:</u> The osmotic pressure is 54307.94 Torr.

<u>Explanation:</u>

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$\pi$ = osmotic pressure of the solution = ?

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R = Gas constant = $62.364\text{ L Torr }mol^{-1}K^{-1}$

T = temperature of the solution = $30^oC=[30+273]K=303K$

Putting values in above equation, we get:

$\pi=3\times 0.958mol/L\times 62.364\text{ L. Torr }mol^{-1}K^{-1}\times 303K\\\\\pi=54307.94Torr$

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3 years ago

6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)

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Taking into account the definition of calorimetry, 0.0185 moles of water are required.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

<h3>Mass of water required</h3>

In this case, you know:

Heat= 92.048 kJ
Mass of water = ?
Initial temperature of water= 34 ºC
Final temperature of water= 100 ºC
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Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× (100 °C -34 °C)

92.048 kJ = 4.186 $\frac{J}{gC}$ × m× 66 °C

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<u><em>m= 0.333 grams</em></u>

<h3>Moles of water required</h3>

Being the molar mass of water 18 $\frac{g}{mole}$ , that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as: