This table models a linear function.

Russ is solving an equation where both sides are linear expressions. he sets the expressions equal to y and graphs the system fi

Dafna1 [17]

The correct option (D).

There are infinitely many intersection points.

<h3>What is liner equation?</h3>

a two-variable equation that, when plotted on a graph, results in a straight line.

<h3>What does intersection point mean?</h3>

The term "point of intersection" refers to the intersection of two lines.

<h3>According to the given information:</h3>

Russ is attempting to solve an equation whose two sides are both linear expressions.

He graphs the system and finds that they are on the same line after setting the expressions to y.

Since both lines are the same, there are an endless number of junction places.

Russ should therefore consider the outcome to be option (D) There are a limitless number of intersections.

To know more about intersection points and linear equations visit:

brainly.com/question/16982453

#SPJ4

I understand that the question you are looking for is:

Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome? There are no intersection points. There is exactly one intersection point. There are exactly two intersection points. There are infinitely many intersection points.Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome?

A. There are no intersection points.

B. There is exactly one intersection point.

C. There are exactly two intersection points.

D. There are infinitely many intersection points

3 0

2 years ago

Evaluate f(t)=-2t2+ 1 for f(-3).

podryga [215]

Answer:

7

Step-by-step explanation:

First, plug-in f(-3) into t in the function:

$f(-3)=-2(-3) +1$

Second, multiply -2 and -3 to get 6:

$f(-3)=-2(-3)+1$ ⇒ $f(-3)=6+1$

Third, add 6 and 1 to get your answer:

$f(-3)= 6+1$ ⇒ $f(-3)=7$

3 0

3 years ago

How many centimeters are there in 1/5 of an inch

Lynna [10]

Answer:

0.508

Step-by-step explanation:

4 0

3 years ago

Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50. Jason went into the same movi

ruslelena [56]

The price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

<em><u>Solution:</u></em>

Let d" be the price of 1 drink

Let "p" be the price of 1 pretzel

Given that, Isabella went into a movie theater and bought 3 drinks and 10 pretzels, costing a total of $54.50

<em><u>Therefore, we can frame a equation as,</u></em>

3 x price of 1 drink + 10 x price of 1 pretzel = 54.50

$3 \times d + 10 \times p = 54.50$

3d + 10p = 54.5 ---------- eqn 1

Jason went into the same movie theater and bought 9 drinks and 5 pretzels, costing a total of $57.25

9 x price of 1 drink + 5 x price of 1 pretzel = 57.25

$9 \times d + 5 \times p = 57.25$

9d + 5p = 57.25 ---------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Multiply eqn 1 by 3

9d + 30p = 163.5 ----- eqn 3

<em><u>Subtract eqn 2 from eqn 3</u></em>

9d + 30p = 163.5

9d + 5p = 57.25

( - ) -----------------------

25p = 106.25

p = 4.25

<em><u>Substitute p = 4.25 in eqn 1</u></em>

3d + 10(4.25) = 54.5

3d + 42.5 = 54.5

3d = 54.5 - 42.5

3d = 12

d = 4

Thus price of 1 drink is $ 4 and price of 1 pretzel is $ 4.25

4 0

3 years ago

skew-symmetric 3 x 3 matrices form as subspace of all 3 x 3 matrices and find a basis for this subspace.

Neporo4naja [7]

Answer:

a) ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

b) therefore Basis of W is

={ ${\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right]$ $,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right]$ $,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]$ }

Step-by-step explanation:

Given the data in the question;

W = { A| Air Skew symmetric matrix}

= {A | A = -A^T }

A ; O⁻ = -O⁻^T O⁻ : Zero mstrix

O⁻ ∈ W

now let A, B ∈ W

A = -A^T B = -B^T

(A+B)^T = A^T + B^T

= -A - B

- ( A + B )

⇒ A + B = -( A + B)^T

∴ A + B ∈ W.

∝ ∈ | R

(∝.A)^T = ∝A^T

= ∝( -A)

= -( ∝A)

(∝A) = -( ∝A)^T

∴ ∝A ∈ W

so by subspace, W is subspace of 3 × 3 matrix

A ∈ W

A = -AT

A = $\left[\begin{array}{ccc}o&a&b\\-a&o&c\\-b&-c&0\end{array}\right]$

= $a\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right]$ $+b\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right]$ $+c\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]$

therefore Basis of W is

={ ${\left[\begin{array}{ccc}0&1&0\\-1&0&0\\0&0&0\end{array}\right]$ $,\left[\begin{array}{ccc}0&0&1\\0&0&0\\-1&0&0\end{array}\right]$ $,\left[\begin{array}{ccc}0&0&0\\0&0&1\\0&-1&0\end{array}\right]$ }

8 0

3 years ago