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Lena [83]
2 years ago
13

A researcher is comparing the effectiveness of three devices designed to help people who snore. There are 210 people who snore p

articipating in the experiment. Using a table of random digits starting from the first row and column, the researcher will randomly place the participants into three equally sized treatment groups suitable for comparison.
Which number range would be needed to label the subjects correctly?

0–2
1–3
000–210
001–210
Mathematics
1 answer:
hjlf2 years ago
8 0

Answer:

the answer is 000-210

Step-by-step explanation:

edge 2021

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Solve the equation 6x+3y=15for y what does y equal if x=2 if x=5
avanturin [10]
6x+3y=15
6*2+3y=15
12+3y=15
      3y=3
        y=1

6x+3y=15
6*5+3y=15
30+3y=15
      3y=-15
        y=-5

The answers is y=1 & -5

3 0
3 years ago
What is the image point of (8, 4) after a translation left 2 units and down 4 units?
tino4ka555 [31]

Answer:

(6, 0 )

Step-by-step explanation:

A translation to the left means subtract 2 from the x- coordinate

A translation down means subtract 4 from the y- coordinate

Then

(8, 4 ) → (8 - 2, 4 - 4 ) → (6, 0 )

5 0
3 years ago
Read 2 more answers
Manny bought 12 pounds of vegetables
finlep [7]

Answer:

Manny bought 3 pounds that were not on sale

Step-by-step explanation:

If 75 % were on sale,  (100% -75% = 25%)  then 25% were not on sale  (The total has to be 100%)

Manny bought 12 pounds of vegetables

To determine how many pounds were not on sale, we take the amount of vegetables purchased and multiply by the percent that were not on sale.

12 * 25%

Change this to decimal form

12 *.25

3

Manny bought 3 pounds that were not on sale


7 0
3 years ago
Read 2 more answers
Please help with math and please show your work will give brainliest
Burka [1]

Answer:

The Elimination Method is based on the Addition Property of Equality. The Addition Property of Equality says that when you add the same quantity to both sides of an equation, you still have equality. We will extend the Addition Property of Equality to say that when you add equal quantities to both sides of an equation, the results are equal.

For any expressions a, b, c, and d,

if  and  then a=bc=da+c=b+d

To solve a system of equations by elimination, we start with both equations in standard form. Then we decide which variable will be easiest to eliminate. How do we decide? We want to have the coefficients of one variable be opposites, so that we can add the equations together and eliminate that variable.

Notice how that works when we add these two equations together:

3x+y=52x−y=0–––––––––––5x=5

The y’s add to zero and we have one equation with one variable.

Let’s try another one:

{x+4y=22x+5y=−2(5.3.3)

This time we don’t see a variable that can be immediately eliminated if we add the equations.

But if we multiply the first equation by −2, we will make the coefficients of x opposites. We must multiply every term on both sides of the equation by −2.

This figure shows two equations. The first is negative 2 times x plus 4y in parentheses equals negative 2 times 2. The second is 2x + 5y = negative 2. This figure shows two equations. The first is negative 2x minus 8y = negative 4. The second is 2x + 5y = -negative 2.

Now we see that the coefficients of the x terms are opposites, so x will be eliminated when we add these two equations.

Add the equations yourself—the result should be −3y = −6. And that looks easy to solve, doesn’t it? Here is what it would look like.

This figure shows two equations being added together. The first is negative 2x – 8y = −4 and 2x plus 5y = negative 2. The answer is negative 3y = negative 6.

We’ll do one more:

{4x−3y=103x+5y=−7

It doesn’t appear that we can get the coefficients of one variable to be opposites by multiplying one of the equations by a constant, unless we use fractions. So instead, we’ll have to multiply both equations by a constant.

We can make the coefficients of x be opposites if we multiply the first equation by 3 and the second by −4, so we get 12x and −12x.

This figure shows two equations. The first is 3 times 4x minus 3y in parentheses equals 3 times 10. The second is negative 4 times 3x plus 5y in parentheses equals negative 4 times negative 7.

This gives us these two new equations:

{12x−9y−12x−20y=30=28

When we add these equations,

\[{12x−9y=30−12x−20y=28–––––––––––––––––−29y=58

\]

the x’s are eliminated and we just have −29y = 58.

Once we get an equation with just one variable, we solve it. Then we substitute that value into one of the original equations to solve for the remaining variable. And, as always, we check our answer to make sure it is a solution to both of the original equations.

Now we’ll see how to use elimination to solve the same system of equations we solved by graphing and by substitution

Step-by-step explanation:

Here is some examples

4 0
2 years ago
F+4/g=6 Solve for F
Svet_ta [14]
\dfrac{f+4}{g}=6\ \  \ \ |multiply\ both\ sides\ by\ g\\\\f+4=6g\ \ \ \ |subtract\ 4\ from\ both\ sides\\\\\boxed{f=6g-4}
5 0
3 years ago
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