1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dimas [21]
4 years ago
12

Two different companies have applied to provide cable television service in a certain region. let p denote the proportion of all

potential subscribers who favor the first company over the second. consider testing h0: p = 0.5 versus ha: p ≠ 0.5 based on a random sample of 25 individuals. let the test statistic x be the number in the sample who favor the first company and x represent the observed value of x.
Mathematics
1 answer:
SpyIntel [72]4 years ago
7 0
The one of the rejection regions which is most appropriate is R1, because x either too large or too small contradicts p=  .5 and supports p is not equal .5 A type I error consists of judging one of the two companies favored over the other when in fact there is a 50-50 split in the population. A type II error will involves judging the split to be 50-50 when it is not.
You might be interested in
Jayden is starting a business selling handmade necklaces. He has decided to invest an initial amount of $300 for advertising, an
shutvik [7]

Answer:

14-8=6/300=50 thats your answer

8 0
3 years ago
Given () = −^3 + 2^2 +(3/2) be the position of a particle moving along the x-axis at time t. At what time will the instantaneous
cestrela7 [59]

Answer:

5.266 secs

Step-by-step explanation:

Lets assume ; p(t) = t^-3 + 2^2 + ( 3/2 ) is the particle position along x-axis

time interval [ 0, 4 ]

Average velocity = Displacement / time

                            = p( b ) - p( a ) /  b - a -------- ( 1 )

where a = 0 , b = 4 ( time intervals )

Back to equation 1

Average velocity = [ ( 4^-3 + 4 + (3/2) ) - ( 0 +  4 + (3/2) ) ] / 4

                             = 3.9 * 10^-3 ----- ( 2 )

Instantaneous velocity = d/dx p(t)

                                      = - 3/t^4  ------ ( 3 )

To determine the time that the instanteous velocity = average velocity

equate equations (2) and (3)

3.9*10^-3 = - 3 / t^4

t^4 = - 3 / ( 3.9 * 10^-3 ) = - 769.231

hence t = \sqrt[4]{- 769.231 } = 5.266 secs

we ignore the negative sign because time can not be in the negative

4 0
3 years ago
Please help ASAP, giving lots of points.
BARSIC [14]
The answers is the last one

6 0
4 years ago
The value of m, if 3,18,m,42 are in proportion
Tom [10]

If its a proportion then

\\ \sf\longmapsto 42-m=m-18

\\ \sf\longmapsto 42+18=m+m

\\ \sf\longmapsto 2m=60

\\ \sf\longmapsto m=\dfrac{60}{2}

\\ \sf\longmapsto m=30

5 0
3 years ago
If 4 units equal 12 inches, what is the value of 1 unit
ser-zykov [4K]

Answer:

1 unit = 3 inches

Step-by-step explanation:

We are given that 4 units = 12 inches.

This can be rewritten as 4x = 12

Then to solve for x, you divide 4 on both sides

so x = 12/4

x = 3

Let me know if you have any questions

3 0
3 years ago
Read 2 more answers
Other questions:
  • He solid shown has two square faces and four rectangular faces. A plane intersects the solid at vertices R, S, T, and U. What is
    14·2 answers
  • An account earns simple interest find the annual interest rate I equals $30 P equals $250 T equals 3 years
    6·1 answer
  • What is 1/4+1/2+x=−3/4?
    9·2 answers
  • Which set of values makes the inequality n > -5 true?
    9·1 answer
  • Whats 2+2322634353662881076464e66​
    9·2 answers
  • Given the statement -12 ≤ -15, which of the following is correct?
    9·1 answer
  • How do you solve this problem?
    7·1 answer
  • Does (10,1) make the inequality 13x+15y greater than or Equal to 19 true?
    10·1 answer
  • Ok no one at my school can get it, who has the crown to get this right 1st out of my whole class lolllll plus ill give brainiest
    9·1 answer
  • How many degress will the hour hand of a well clock move from 1:00am to 4:00am
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!