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Dimas [21]
3 years ago
12

Two different companies have applied to provide cable television service in a certain region. let p denote the proportion of all

potential subscribers who favor the first company over the second. consider testing h0: p = 0.5 versus ha: p ≠ 0.5 based on a random sample of 25 individuals. let the test statistic x be the number in the sample who favor the first company and x represent the observed value of x.
Mathematics
1 answer:
SpyIntel [72]3 years ago
7 0
The one of the rejection regions which is most appropriate is R1, because x either too large or too small contradicts p=  .5 and supports p is not equal .5 A type I error consists of judging one of the two companies favored over the other when in fact there is a 50-50 split in the population. A type II error will involves judging the split to be 50-50 when it is not.
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8 1/5 - 3 4/5 help me PLEEEEEASE
Alex17521 [72]

Answer:

1/5x(41-19h)

41/5-19/5h

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
a recipe for 1 handmade pizza calls for 2 1/2 cups all purpose flour. Showing your work below, how many cups of all purpose flou
KatRina [158]
You need to use the cross product method to find your answer :

1 pizza = 2 ½ cups
3 pizzas = × cups

((2 ½) • 3) ÷ 1 = × cups

7 ½ ÷ 1 = × cups

7 ½ = × cups

⇨ So your answer is: You would need to use 7 ½ cups of flour to make 3 handmade pizzas!

There you go. I really hope this helped, if there’s anything just let me know! ☻
3 0
3 years ago
1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t
Sophie [7]

1)\text{   }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}

So after 70 days, 5.625 mg will be left

4 0
1 year ago
I cant figure out the awnser<br>9+10​
o-na [289]

Answer:

I'm sorry I don't have a functioning brain anymore-

<em>but I think it's 21.</em>

<em />

3 0
3 years ago
Read 2 more answers
Fill in the blank:
sp2606 [1]
<span>I can be wrong, but I think that the answer is: To find the values of p, q, r and s, you should start by finding all factor pairs of the leading coefficiant and constant term. </span>
4 0
3 years ago
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