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2 years ago

It would be the first one right...?

Mathematics

2 answers:

Contact [7]2 years ago

7 0

The answer is the second one

Ludmilka [50]2 years ago

6 0

Answer:

I say the second one but I could be wrong..

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Given a sample mean difference of 23, a standard error of 4.2, and a critical t value of 2.262, what are the values for the conf

erastova [34]

Answer: (13.4996, 32.5004)

Step-by-step explanation:

The confidence interval for mean difference is given by :-

$(\overline{x}_1-\overline{x}_2)\pm t^*\times SE$ ,

where $(\overline{x}_1-\overline{x}_2)$ = sample mean difference .

$t^*$ = critical t value (two-tailed)

SE= Standard error.

Given : $(\overline{x}_1-\overline{x}_2)=23$

$t^*=2.262$

SE= 4.2

Now, the confidence interval for mean difference will be :-

$23\pm (2.262)\times (4.2)\\\\= 23\pm9.5004\\\\=(23-9.5004,\ 23+9.5004)\\\\=(13.4996,\ 32.5004)$

Hence, the required confidence interval : (13.4996, 32.5004)

8 0

3 years ago

Helppp Urgebttt!!!

Alenkasestr [34]

C because there are 60 seconds in a minute so if you multiply 600 x 60 you get 36000

4 0

3 years ago

Look at the figure shown below.

Sveta_85 [38]

Answer:

Step by step explanation:

7 0

3 years ago

Using your knowledge of exponential and logarithmic functions and properties, what is the intensity of a fire alarm that has a s

Ierofanga [76]

Option B:

$I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$

Solution:

Given sound level = 120 decibel

To find the intensity of a fire alarm:

$$\beta=10\log\left(\frac{I}{I_0} \right)$

where $I_0=1\times10^{-12}\ \text {watts}/ \text m^2}$

Step 1: First divide the decibel level by 10.

120 ÷ 10 = 12

Step 2: Use that value in the exponent of the ratio with base 10.

$10^{12}$

Step 3: Use that power of twelve to find the intensity in Watts per square meter.

$$10^{12}=\left(\frac{I}{I_0} \right)$

$$10^{12}=\left(\frac{I}{1\times10^{-12}\ \text {watts}/ \text m^2} \right)$

Now, do the cross multiplication,

$I=10^{12}\times1\times\ 10^{-12} \ \text {watts}/ \text m^2}$

$I=1\times\ 10^{12-12} \ \text {watts}/ \text m^2}$

$I=1\times\ 10^{0} \ \text {watts}/ \text m^2}$

$I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$

Option B is the correct answer.

Hence $I=1.0\times\ 10^{0} \ \text {watts}/ \text m^2}$ .

5 0

4 years ago

HELP MEEEEE EASY DUE IN A MINSS<br> What is the prime factorization of 990?

alex41 [277]

Answer:

11 is one of the factors! The orange divisor(s) above are the prime factors of the number 990. If we put all of it together we have the factors 2 x 3 x 3 x 5 x 11 = 990.

Step-by-step explanation:

3 0

3 years ago