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1 year ago

Can anyone help me i really need it rn

Mathematics

1 answer:

Hunter-Best [27]1 year ago

4 0

Answer:

11. g

12. f

13. e (add all the frequencies)

14. d

15. c (eg. 17.5 -8.5 = 9)

16. b

17. a

Let me know if you have any questions.

Hope this helps!

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I'm not sure how to do the problem in the image I attached below... help.

yanalaym [24]

The answer is 5
Your welcome :)

3 0

2 years ago

Read 2 more answers

Suppose you are conducting a study to determine if women are better drivers than men. You send your survey to over 1000 students

julsineya [31]

Answer:

555.56

Step-by-step explanation:

Purpose of the study: To determine if women are better drivers than men.

Survey or Opinion population: 1,000

You are experimenting on 9 out of a thousand opinions.

5 of these opinions are that women are better drivers

4 of these opinions are that women are not better drivers

You want to know the sample (full sample size is 9) proportion for women as better drivers; using the large sample method. This method is also called the asymptotic method.

This involves approximating the desired statistic, with just a small fraction of the population; in this case, 9/1000.

This approximation will get more and more accurate as sample size increases and you know that a larger sample size gives a better representation and interpretation of the population preference!

So using ratio, the sample proportion for women as the better drivers is given by:

5/9 x 1000 = 555.56 opinions

8 0

2 years ago

Write the equation. 5 more than a number times 2 is 2

suter [353]

$(5 +n)\cdot2 = 2$

$3(2 -n) > 7$

8 0

2 years ago

1. Eight people work in an office. They are paid hourly rates of 12£,15£,15£,14£,14£,13£,14£,13£

bearhunter [10]

Answer:

mean=110/8 =13.75 pounds; median=14 pounds; mode=14 pounds; average=13.75 pounds

Step-by-step explanation:

mean=add all the numbers together to get total then divide that total by the number of amounts present 12, 15, 15, 14, 14, 13, 14, 13 =110, then 110/8=13.75 pounds

mode=arrange amounts in order (smallest to largest), then determine which amount appears more than the other amounts 12, 13, 13, 14, 14, 14, 15, 15 =14 appears the most

median=organize numbers from smallest to greatest, count how many there are, then determine which number appears in the middle of all of them 12, 13, 13, 14, 14, 14, 15, 15 = there are 8 numbers present but 14 is in the middle; answer =14

average= take total of mean, then divide it by the number of amounts that appear 110/8 =13.75

8 0

2 years ago

Casper bought some pencils at .50 each. He had $3 left after the purchase. If he wanted to buy the same number of note pads at .

Nesterboy [21]

Answer:

Required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

Solution:

Let’s assume number of pencils purchased by Casper = x

As given price of each pencil is 0.50 , so price of x pencils = 0.50x = 0.5x

Also given that she was left with $3 after buying x pencils.

So initial amount which was with casper = price of x pencils + amount he was left with.

=> Initial amount with Casper = 0.5x + 3 ------(1)

Now consider second scenario

If Casper wanted to buy same number of notepad at price of 0.80 each , then

Total amount need for x notepad = 0.80x = 0.8x

But its also given that he will be short of $1.5.

So initial amount with Casper = 0.80x – 1.5 ------(2)

On equating initial amount with casper using equation (1) and equation(2) we get

0.5x + 3 = 0.8x – 1.5

=> 0.8x – 0.5x = 3 + 1.5

=> 0.3x = 4.5

=> 0.3x – 4.5 = 0

=> 3x – 45 = 0

So linear equation for x that is number of pencils he purchased is 3x – 45 = 0 where variable x represents number of pencils.

On solving the linear equation 3x – 45 = 0 for x we get

3x = 45

x = 15

Hence required linear equation to get number of pencils purchased by Casper is 3x – 45 = 0 where x represents number of pencils and number of pencils Casper purchased = 15.

7 0

3 years ago

Can anyone help me i really need it rn​

Can anyone help me i really need it rn