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xenn [34]
3 years ago
11

There are a total of 64 students in a drama club and a yearbook club. The drama club has 14 more students than the yearbook club

.a. Write a system of linear equations that represents this situation. Let x represent the number of students in the drama club and y represent the number of students in the yearbook club
Mathematics
1 answer:
yawa3891 [41]3 years ago
8 0
Answer:

39 students in the drama club, 25 in the yearbook club.

Explanation:

X=number of students in the drama club
Y=number of students in the yearbook club

X+Y=64
X−14=y
Subtract the equations
X−X+Y+14=64−Y
Y+14=64−Y
Subtract 14, add Y
Y+Y+14−14=64−14−Y+Y
2Y=50
Divide by 2
Y=25
X+25=64
Subract 25
X=64−25
X=39

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astra-53 [7]

Answer:

a. a = 1, b = -5, c = -14

b. a = 1, b = -6, c = 9

c. a = -1, b = -1, c = -3

d. a = 1, b = 0, c = -1

e. a = 1, b = 0, c = -3

Step-by-step explanation:

a. x-ints at 7 and -2

this means that our quadratic equation must factor to:

(x-7)(x+2) = 0

FOIL:

x^2 + 2x - 7x - 14 = 0

Simplify:

x^2 - 5x - 14 = 0

a = 1, b = -5, c = -14

b. one x-int at 3

this means that the equation will factor to:

(x-3)^2=0

FOIL:

x^2 - 3x - 3x +9 = 0

Simplify:

x^2 - 6x + 9 = 0

a = 1, b = -6, c = 9

c. no x-int and negative y must be less than 0

This means that our vertex must be below the x-axis and our parabola must point down

There are many equations for this, but one could be:

-x^2-x-3=0

a = -1, b = -1, c = -3

d. one positive x-int, one negative x-int

We can use any x-intercepts, so let's just use -1 and 1

The equation will factor to:

(x+1)(x-1)=0

This is a perfect square

FOIL:

x^2-1=0

a = 1, b = 0, c = -1

e. x-int at \sqrt{3} , -\sqrt{3}

our equation will factor to:

(x+\sqrt{3} )(x-\sqrt{3)} =0

This is also a perfect square

FOIL and you will get:

x^2 - 3 = 0

a = 1, b = 0, c = -3

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Step-by-step explanation:

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