The ratio of 6 yards to 9 feet is 1/2 but I can't see where the missing value is
Answer:
T must be 3/(3+1) or 3/4ths of the way between point d and f.
Take (dx, dy) and add 3/4 (fx-dx, fy-dy) by components and that will be point T (Tx, Ty)
You find the distances between d and f in x and y and then move 3/4 of that distance from d.
Step-by-step explanation:
Im not too sure, I got the answer from my last test. It might be wrong
This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Answer:
8x^3-7x^2-11x+9
Step-by-step explanation:
(8x^3-5x-1)-(7x^2+6x-10)
remove unnesasary ( )
8x^3-5x-1 -(7x^2+6x-10)
the distribute
8x^3-5x-1 -7x^2-6x+10
combine like terms
8x^3-11x+9-7x^2
use the communative property to reorder the equation
8x^3-7x^2-11x+9
