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2 years ago

What is the inverse function of 3/5y+9

Mathematics

1 answer:

marissa [1.9K]2 years ago

7 0

Answer:

Step-by-step explanation:

I'm not really sure how, try telling her to ask her teacher, it's kinda hard to explain but, yeah 15.

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Which graphs below have a domain of all real numbers? Which have a range of all real numbers? Which are functions?

slava [35]

Answer:

Step-by-step explanation:

From the picture attached,

Graph (A)

Domain of the function : (-∞, ∞) or a set of real numbers

Range of the function : (-∞, ∞) or a set of real numbers

Graph (B),

Domain : (-∞, ∞) Or a set of real numbers

Range : (-∞, 6] Or x ≤ 6

Graph (C),

Domain : [-2, ∞) or x ≥ -2

Range : (-∞, ∞) Or a set of real numbers

Therefore, Graphs (A), (B) have the domain of all real numbers and Graph (C) has the range of all real numbers.

Since all the parabolas are not the functions,

Therefore, Graph (C) is not a function. Graphs (A) and (B) are the functions.

3 0

3 years ago

The stem-and-leaf plot shows the amount of money each student in Spanish club collected for charity this semester. How many male

HACTEHA [7]

72 because I helped you show do you Andreas show me too

7 0

2 years ago

Read 2 more answers

Use the graph of f below. Assume the entire function is graphed below. Find the domain

enot [183]

ANSWER

The domain of the function is

$- 3 \leqslant x \leqslant 6$

[-3,6]

EXPLANATION

The domain of a function refers to the values of x for which the function is defined.

From the graph, we can see that the function begins at (-3,6) and ends at (6,-4).

Therefore the function is defined for x=-3 to x=6.

Hence the domain of the function is

$- 3 \leqslant x \leqslant 6$

[-3,6]

5 0

3 years ago

7+3 to the second power+(12-8) divided by 2x 4 is

cupoosta [38]

$\bf \stackrel{\mathbb{P~E~M~D~A~S}}{7+3^2+(12-8)\div 2\times 4}\implies 7+3^2+(\stackrel{\downarrow }{4})\div 2\times 4\implies 7+\stackrel{\downarrow }{9}+(4)\div 2\times 4 \\\\\\ 7+9+\stackrel{\downarrow }{2}\times 4\implies 7+9+\stackrel{\downarrow }{8}\implies \stackrel{\downarrow }{16}+8\implies 24$

5 0

3 years ago

"Quadrilateral ABCD underwent a sequence of transformations to give quadrilateral A′B′C′D′. Which transformations could have tak

suter [353]

The quadrilateral ABCD have vertices at points A(-6,4), B(-6,6), C(-2,6) and D(-4,4).

Translating 10 units down you get points A''(-6,-6), B''(-6,-4), C''(-2,-4) and D''(-4,-6).

Translaitng 8 units to the right you get points A'(2,-6), B'(2,-4), C'(6,-4) and D'(4,-6) that are exactly vertices of quadrilateral A'B'C'D'.

Answer: correct choice is B.

6 0

3 years ago

Read 2 more answers