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ruslelena [56]
2 years ago
15

BRAINLIESTT What is the square root of 6?

Mathematics
2 answers:
ivann1987 [24]2 years ago
6 0

Answer:

2.44948974278

i think it's this one .

kap26 [50]2 years ago
3 0
The square root of 6 is 2.44
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Simplify <br> (6x−2)2(0.5x)4. Show your work.
WARRIOR [948]

Answer:

{24x}^{2}  - 8x

Step-by-step explanation:

just a warning. not 100% sure if this is right, its just what i did. and yes its legal math. i think lol.

so i distributed the 2 to the 0.5x, getting just x. then multiplying that x by 4 getting 4x. next i just distributed the 4x to the 6x-2. getting the answer bc multiplying an x by an x gets you and x^2. so you get 24x^2 (bc 4 times 6 is 24) and -8x bc 4x times -2 is -8x

5 0
2 years ago
Factor the polynomial expression 3x² + 2.
mel-nik [20]

Answer:

\boxed{\left(x+i\sqrt{\frac{2}{3}}i \right)\left(x-i\sqrt{\frac{2}{3}}i \right)}

Step-by-step explanation:

Setting the expression equal to zero to find the roots,

3x^2 +2=0\\\\3x^2 =-2\\\\x^2 =-\frac{2}{3}\\\\x=\pm i\sqrt{\frac{2}{3}}

This means that

3x^2 +2=\boxed{\left(x+i\sqrt{\frac{2}{3}}i \right)\left(x-i\sqrt{\frac{2}{3}}i \right)}

5 0
1 year ago
At the movie theatre, child admission is $6.10 and adult admission is $9.20 . On Thursday, three times as many adult tickets as
natita [175]

Answer:

21 child tickets.

Step-by-step explanation:

Let x represent number of adult tickets and y represent number of child tickets.  

We have been given that on Thursday, three times as many adult tickets as child tickets were sold. We can represent this information in an equation as:

x=3y...(1)

We have been given that at a the movie theater, child admission is $6.10 and adult admission is $9.20.The all tickets were sold for a total of $707.70. We can represent this information in an equation as:

9.20x+6.10y=707.70...(2)  

Upon substituting equation (1) in equation (2), we will get:

9.20(3y)+6.10y=707.70  

27.6y+6.10y=707.70

33.7y=707.70

\frac{33.7y}{33.7}=\frac{707.70}{33.7}

y=21

Therefore, 21 child tickets were sold on Thursday.

4 0
3 years ago
Gamal is buying ham and turkey to make sandwiches for a party. At most, he can spend $50, and he must buy more than 8 pounds of
IRINA_888 [86]
H +t = 8
$6h + $7t ≤$50

h+t = 8
h +t-t=8-t
h= 8-t

$6(8-t) + $7t ≤$50
48-6t +7t≤50
48-48+t≤50-48
t ≤ 2
h=6

$6(6) + $7(2) ≤$50
36 + 14 ≤ 50
50≤50

He can buy 6 pounds of ham and 2 pounds of turkey
3 0
3 years ago
Read 2 more answers
A gas at standard temperature and pressure was measured as having a mass of 1485 grams (g) in a volume of 750 liters (L). Which
tangare [24]

Answer:

Here we will use the relation:

Density = mass/volume.

We know that:

Mass = 1485g

Volume = 750L

Density = 1485g/750L = 1.98 g/L

We do not have the options in order to select the correct one, but knowing this density, we can suppose the possible gases.

Two "common" gases with densities similar to this one are:

Carbon Dioxide, with d = 1.977 g/L

Dinitrogen Monoxide, with d = 1.977 g/L

In both cases, if we round up we will get the same density that we calculated at the beginning, so either of these can be the correct option.

6 0
3 years ago
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