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muminat
2 years ago
14

What is the equation of the line that passes through the point (-5,0) and has a slope of3/5

Mathematics
1 answer:
Lostsunrise [7]2 years ago
3 0

Answer:

y = 3/5x + 3

Step-by-step explanation:

→ Write down in y = mx + c

y = 3/5x + c

→ Substitute in coordinates

0 = -3 + c

→ Find c

c = 3

→ Rewrite

y = 3/5x + 3

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Explanation:

\begin{gathered} c)\text{ Change in input = 4 - 3 , 3 - 2, 2 -1 } \\ \text{change in input = 1 (it is constant )} \\ \text{The output depends on the input.} \end{gathered}\begin{gathered} To\text{ get output 2: (1 }\times1\text{ )+ 1 = 1 +1 = 2} \\ To\text{ get output 5: (2}\times2)\text{ + 1 = 4 + 1 = 5} \\ To\text{ get output 10: (3}\times3)\text{ + 1 = 9 + 1 = 10} \\ To\text{ get output 17: (4}\times4)\text{ + 1 = 16 + 1 = 17} \\ To\text{ get output 26: (5}\times5)\text{ + 1 = 25 + 1 = 26} \end{gathered}\begin{gathered} \text{Formula for the Process = (input}\times\text{ input) }+\text{ 1} \\ Process=(input)^2\text{ }+\text{ 1} \\ \text{output = (input}\times\text{ input) }+\text{ 1} \end{gathered}

\begin{gathered} d)\text{ rate of change = }\frac{change\text{ in output }}{\text{change in input}} \\ \text{rate of change = }\frac{-5-(-15)}{0-(-2)}\text{ = }\frac{10-(-5)}{3-0}\text{ = }\frac{15-10}{4-3} \\ \text{rate of change = }\frac{10}{2}\text{ = }\frac{15}{3}=\frac{5}{1} \\ \text{rate of change = 5} \end{gathered}\text{output = input + 5}

5 0
1 year ago
Find the volume of this
11111nata11111 [884]

Answer:

37.8 yd^3

Step-by-step explanation:

base area = (4.5 x 2.8)/2 = 6.3 yd^2

Volume = 6.3 x 6 = 37.8 yd^3

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Answer:

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Step-by-step explanation: there is 16oz in every lb. so 16 X’s 7=112 now minus the 8ozs used. 112-8=104 oz’s left. The snack bags are 4 ozs so you Divide 4/104=26


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