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muminat
3 years ago
14

What is the equation of the line that passes through the point (-5,0) and has a slope of3/5

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

y = 3/5x + 3

Step-by-step explanation:

→ Write down in y = mx + c

y = 3/5x + c

→ Substitute in coordinates

0 = -3 + c

→ Find c

c = 3

→ Rewrite

y = 3/5x + 3

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Does anyone know this? <br> Will mark brainliest !!!!
stich3 [128]

Answer:

x=4

y=4√5

Step-by-step explanation:

Set up 3 right triangles and mark their respective angles. The largest will have sides (in typical a,b,c[hypotenuse] order) y, z, and 10. The middle 8, x, and y. The smallest x,  2, and z.

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Then using the larger and middle triangles, do the same for the A and C sides.

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5 0
3 years ago
The softball team is fundraising by washing cars. They paid $55.25 for supplies. If they
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7 0
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Use the rectangle hexagon with side length 10 meters to fill in the missing information
Vlada [557]

Answer:

A_h=150\sqrt{3}\ m^2

Step-by-step explanation:

<u>Regular Hexagon</u>

For the explanation of the answer, please refer to the image below. Let's analyze the triangle shown inside of the hexagon. It's a right triangle with sides x,y, and z.

We know that x is half the length of the side length of the hexagon. Thus

x=5 m

Note that this triangle repeats itself 12 times into the shape of the hexagon. The internal angle of the triangle is one-twelfth of the complete rotation angle, i.e.

\theta=360/12=30^o

Now we have \theta, the height of the triangle y is easily found by

\displaystyle tan30^o=\frac{x}{y}

Solving for y

\displaystyle y=\frac{x}{tan30^o}=\frac{5}{ \frac{1} {\sqrt{3} }}=5\sqrt{3}

The value of z can be found by using

\displaystyle sin30^o=\frac{x}{z}

\displaystyle z=\frac{x}{sin30^o}=\frac{5}{\frac{1}{2}}=10

The area of the triangle is

\displaystyle A_t=\frac{xy}{2}=\frac{5\cdot 5\sqrt{3}}{2}=\frac{25\sqrt{3}}{2}

The area of the hexagon is 12 times the area of the triangle, thus

\displaystyle A_h=12\cdot A_t=12\cdot \frac{25\sqrt{3}}{2}=150\sqrt{3}

\boxed{A_h=150\sqrt{3}\ m^2}

6 0
3 years ago
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