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Leona [35]
3 years ago
15

Calculate the molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water. The molar mass of C6

H12O6 is 180.156 g/mol.
Chemistry
1 answer:
Maslowich3 years ago
5 0

The molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.

<h3>HOW TO CALCULATE MOLAR CONCENTRATION:</h3>
  • The molar concentration of a solution can be calculated by dividing the number of moles by its volume.

  • According to this question, there are 469 grams of C6H12O6 in 82 milliliters of water.

The number of moles = 469g ÷ 180.156g/mol = 2.6mol

Volume of water in litres = 82/1000 = 0.082L

Concentration of solution = 2.6mol ÷ 0.082L = 31.71M

Therefore, the molar concentration of a solution containing 469 grams of C6H12O6 in 82 milliliters of water is 31.7M.

Learn more about concentration at: brainly.com/question/202460

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Predict whether the changes in enthalpy, entropy, and free energy will be positive or negative for the freezing of water, and ex
Dafna11 [192]

Answer:

Explanation:

The total energy or intrinsic energy of a system is called the enthalpy. In thermochemistry, we have two types of enthalpy changes which are:

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For the freezing of water, the enthalpy change is an exothermic one. Exothermic changes are designated as negative. In this chemical change, heat is liberated to the surroundings and this leaves the environment at a much higher temperature. In freezing, the enviroment gains more heat as the material begins to cool to lower temperature.

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8 0
3 years ago
32
myrzilka [38]

Answer:

0.305 mol

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Ca(NO) is not a molecule. I think you meant to type Ca(NO3)2, which is calcium nitrate.

The moles of a compound is equal to is mass divided by its molar mass.

The molar mass of Ca(NO3)2 is 164.09 g/mol.

50.0 / 164.09 = 0.305

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