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3 years ago

According to the Brensted-Lowry model write the equation for provided acid showing

Chemistry

1 answer:

Taya2010 [7]3 years ago

3 0

Answer:

i dont know sorry

Explanation:

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20g of butanedioic acid were shaken with a mixture of 100 cm3 ether and 100 cm3 water at 298K. After titration with standard sod

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Answer:

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Explanation: It's Hard.

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3 years ago

If an atom has the electron configuration 1s22s22p 1 , how many electrons must it gain to achieve an octet?

konstantin123 [22]

According to octet rule element has eight electrons in its valence shell.This give it the same electronic configuration as a group 18 elements.Atom with electronic configuration 1s2 2s2 2p1 require five electrons to achieve octet. This is because the valence electrons are 3 in 2s2 and 2p1 and hence require 5 electrons to be filled.

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Oliga [24]

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3 years ago

Do the tests performed to identify DNA exclude the presence of RNA?

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DNA and RNA can also be ISOLATED from the same biological sample.

So the answer is no, both DNA and RNA are together.

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Write a balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air.

Lelechka [254]

Answer: The balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

Explanation:

When a substance tends to gain oxygen atom in a chemical reaction and loses hydrogen atom then it is called oxidation reaction.

For example, chemical equation for oxidation of methane is as follows.

$CH_{4} + O_{2} \rightarrow CO_{2} + H_{2}O$

Number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 2

Number of atoms present on product side are as follows.

C = 1
H = 2
O = 3

To balance this equation, multiply $O_{2}$ by 2 on reactant side. Also, multiply $H_{2}O$ by 2 on product side. Hence, the equation can be rewritten as follows.

$CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$

Now, the number of atoms present on reactant side are as follows.

C = 1
H = 4
O = 4

Number of atoms present on product side are as follows.

C = 1
H = 4
O = 4

Since, the atoms present on both reactant and product side are equal. Therefore, this equation is now balanced.

Thus, we can conclude that balanced equation for the complete oxidation reaction that occurs when methane (CH4) burns in air is $CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O$ .

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3 years ago